coloring_nested_tire_graphs: rename induced tire graph C -> T_{C'}
In the tire-component lemma the induced subgraph that becomes the tire
graph was named C, clashing with C used everywhere else for cycles
(seam cycles C_T, cycle graphs C_n, the seam cycle C in Def 1.16).
Rename it to T_{C'} throughout the lemma statement, its proof, and the
degenerate-boundary remark, so C/C'/C_T are uniformly reserved for
cycles and components.
Co-Authored-By: Claude Opus 4.8 <noreply@anthropic.com>
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This is pdfTeX, Version 3.141592653-2.6-1.40.24 (TeX Live 2022) (preloaded format=pdflatex 2022.10.5) 29 MAY 2026 23:25
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This is pdfTeX, Version 3.141592653-2.6-1.40.24 (TeX Live 2022) (preloaded format=pdflatex 2022.10.5) 1 JUN 2026 00:17
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@@ -546,7 +546,7 @@ mr/m/it/10 has $\OMS/cmsy/m/n/10 j\OML/cmm/m/it/10 V\OT1/cmr/m/n/10 (\OML/cmm/m
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@@ -576,7 +576,7 @@ ve/2022/texmf-dist/fonts/type1/public/amsfonts/cm/cmsy7.pfb></usr/local/texlive
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@@ -298,17 +298,17 @@ outer face (such an embedding exists for any planar graph and any
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single-vertex source). For $d \geq 0$, let $C'$ be a connected
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component of the depth-$d$ dual subgraph $G'_d$, with faces $F_{C'}$,
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bounding vertices $V_{C'}$, and region $R_{C'}$ as in
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Definition~\ref{def:dual-component}; let $C := G[V_{C'}]$ inherit its
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Definition~\ref{def:dual-component}; let $T_{C'} := G[V_{C'}]$ inherit its
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embedding from $\Pi_G$.
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Then $C$, with the inherited embedding, is a tire graph in the sense of Definition~\ref{def:tire-graph}. Its outer boundary
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Then $T_{C'}$, with the inherited embedding, is a tire graph in the sense of Definition~\ref{def:tire-graph}. Its outer boundary
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$B_{\mathrm{out}}$ is the side of $R_{C'}$ closer to $S$ in $\Pi_G$,
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namely the level-$d$ subgraph $G[V_{C'} \cap L_d]$ (a simple cycle or
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single vertex); its inner outerplanar graph is $O = G[V_{C'} \cap
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L_{d+1}]$, and its inner boundary $B_{\mathrm{in}}$ is the outer-face
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boundary closed walk of $O$ in the inherited embedding (a simple cycle
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when $O$ is $2$-connected, a non-simple closed walk in general). The
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triangular faces of $C$ inside the closed boundary region are exactly
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triangular faces of $T_{C'}$ inside the closed boundary region are exactly
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the faces of $G$ in $F_{C'}$.
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\end{lemma}
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@@ -325,7 +325,7 @@ both outerplanar.
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at level $d$, and adjacent vertices in $G$ differ in level by at most
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$1$; combined with $\delta_G(d_f) = d$, this forces
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$V(f) \subseteq L_d \cup L_{d+1}$. Hence $V_{C'} \subseteq L_d \cup
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L_{d+1}$, and $C$ has vertex partition
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L_{d+1}$, and $T_{C'}$ has vertex partition
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$V_{C'} = (V_{C'} \cap L_d) \sqcup (V_{C'} \cap L_{d+1})$.
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\emph{Boundary edges are monochromatic in level.} Each edge $e$ on
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@@ -370,7 +370,7 @@ necessarily a simple cycle).
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\emph{Outer boundary.} Because $S$ lies on the outer face of $\Pi_G$,
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the boundary curve(s) of $R_{C'}$ on the $L_d$ side are closer to $S$
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in the embedding. In the inherited embedding of $C$, the unique
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in the embedding. In the inherited embedding of $T_{C'}$, the unique
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unbounded face is the merged region containing the rest of $\Pi_G$
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outside $R_{C'}$ on the $S$ side, so its boundary --- a simple cycle
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on $L_d$ (or a single vertex when $V_{C'} \cap L_d = \{v_0\}$, the
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@@ -393,9 +393,9 @@ precisely to the multiple connected components or bridge crossings of
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$O$, and the outer-face boundary closed walk of $O$ captures them
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collectively.
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\emph{Tire structure.} The triangular faces of $C$ inside the closed
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\emph{Tire structure.} The triangular faces of $T_{C'}$ inside the closed
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boundary region are by construction the depth-$d$ faces in $F_{C'}$,
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and the edges of $C$ are $E(B_{\mathrm{out}}) \cup E(O) \cup
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and the edges of $T_{C'}$ are $E(B_{\mathrm{out}}) \cup E(O) \cup
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E_{\mathrm{ann}}$ where $E_{\mathrm{ann}}$ are the edges of $G$
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between $V_{C'} \cap L_d$ and $V_{C'} \cap L_{d+1}$ that bound a face
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of $F_{C'}$.
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@@ -456,7 +456,7 @@ where $C'$ is its component of $G'_d$. So $\bigcup_{R \in
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\begin{remark}
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\label{rem:tire-component-degenerate}
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Either boundary part of $C$ in Lemma~\ref{lem:tire-component} may be
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Either boundary part of $T_{C'}$ in Lemma~\ref{lem:tire-component} may be
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degenerate. At $d = 0$ with single-vertex source $S = \{v_0\}$ the
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unique component of $G'_0$ has $V_{C'} \cap L_0 = \{v_0\}$ as the
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degenerate \emph{outer} boundary and $V_{C'} \cap L_1$ a cycle (the
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