coloring_nested_tire_graphs: notation cleanup pass
Define previously-implicit objects and unify conventions:
- define level sets L_d (and L_{<d}, L_{>=d}) in the Levels definition
- factor G'_d, F_{C'}, V_{C'}, R_{C'} into a standalone definition
before Prop 1.6, removing the forward reference
- name the annular faces F_ann and state the tire-graph tuple form
T = (B_out, O, E_ann) in the tire-graph definition
- ground the full tire dual D(T) where Gamma is introduced
- normalize tree superscripts (0)/(p)/(c) to the tire-symbol form
(T_0)/(T_p)/(T_c)
- resolve the boundary-count clash: use nu = |V(B_in)| (inner) and
mu = |V(B_out)| (outer) throughout, freeing n for |V(G)|
Co-Authored-By: Claude Opus 4.8 <noreply@anthropic.com>
This commit is contained in:
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\citation{bauerfeld-nested-tire-duals}
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\@writefile{lof}{\contentsline {figure}{\numberline {2}{\ignorespaces A tire graph with non-degenerate boundaries: outer boundary $B_{\mathrm {out}}$ a $6$-cycle on vertices $0,\dots ,5$ (blue), inner boundary $B_{\mathrm {in}}$ a $4$-cycle on vertices $6,\dots ,9$ (red), inner outerplanar graph $O = B_{\mathrm {in}} \cup \{7\text {--}9\}$ (with one chord, orange), and $E_{\mathrm {ann}}$ (grey) tiling the annulus between $B_{\mathrm {out}}$ and $B_{\mathrm {in}}$ by ten triangular faces.}}{3}{}\protected@file@percent }
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\@writefile{lof}{\contentsline {figure}{\numberline {2}{\ignorespaces A tire graph with non-degenerate boundaries: outer boundary $B_{\mathrm {out}}$ a $6$-cycle on vertices $0,\dots ,5$ (blue), inner boundary $B_{\mathrm {in}}$ a $4$-cycle on vertices $6,\dots ,9$ (red), inner outerplanar graph $O = B_{\mathrm {in}} \cup \{7\text {--}9\}$ (with one chord, orange), and $E_{\mathrm {ann}}$ (grey) tiling the annulus between $B_{\mathrm {out}}$ and $B_{\mathrm {in}}$ by ten triangular faces.}}{4}{}\protected@file@percent }
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\@writefile{lof}{\contentsline {figure}{\numberline {3}{\ignorespaces Case 1 ($R$ = disk, $k = 6$). The apex $v_0$ sits at the centre; the non-degenerate boundary $B_{\mathrm {non-deg}}$ (red) is the hexagonal outer cycle; spokes (grey) triangulate the disk into a fan of $6$ triangles around $v_0$. Each triangle has two spoke edges (interior, contributing $\Gamma $-edges) and one boundary edge (contributing a leaf in $D(T)$, no $\Gamma $-edge). The inner dual $\Gamma $ (blue) is the cycle $C_6$ formed by the six annular face centroids, a manifestly outerplanar graph.}}{8}{}\protected@file@percent }
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\citation{bauerfeld-nested-tire-duals}
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\@writefile{lof}{\contentsline {figure}{\numberline {4}{\ignorespaces Case 2 ($R$ = annulus) with $O$ a barbell. $B_{\mathrm {out}}$ is the outer hexagon (red); $O$ has two triangles $\{a_1, a_2, a_3\}$ and $\{b_1, b_2, b_3\}$ joined by the bridge $a_3\text {--}b_1$ (all light red). The annulus is triangulated by $14$ annular triangles: $6$ ``outer-cap'' triangles (one per outer edge), $6$ ``inner-cap'' triangles (one per non-bridge edge of $O$), and $2$ ``bridge-cap'' triangles $\{u_0, a_3, b_1\}$ and $\{u_3, a_3, b_1\}$ adjacent to the bridge. Each blue dot sits at the centroid of an annular triangle; blue edges connect dual vertices whose triangles share an interior annular edge (spoke or bridge). The two bridge-cap vertices have $\Gamma $-degree $3$ (their triangles have no boundary edge) and are joined by the dashed blue \emph {chord} corresponding to the bridge; the remaining $13$ edges form the Hamilton cycle that wraps around the annulus. All $14$ vertices lie on the outer face of the cycle-with-chord embedding, so $\Gamma \cong \Theta (1, 7, 7)$ is outerplanar.}}{9}{}\protected@file@percent }
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\citation{tait-original}
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\newlabel{thm:tait-tire}{{1.15}{10}}
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\@writefile{lof}{\contentsline {figure}{\numberline {5}{\ignorespaces Tire-tree decomposition (Theorem\nonbreakingspace 1.19\hbox {}) on a $13$-vertex maximal planar example $G$ with five BFS levels. $(a)$ $G$ with vertex source $v_0$ and $\ell _G \in \{0,1,2,3,4\}$; four nested seams are highlighted, $C_{T_R} = \{a,b,c\}$ (orange), $C_{T_L} = \{a,c,d\}$ (red, including the chord $a$-$c$ shared with $C_{T_R}$), $C_{T_{LL}} = \{f_1, f_2, f_3\}$ (purple), $C_{T_{LLL}} = \{g_1, g_2, g_3\}$ (teal). Inset: the rooted tree of tire treads $\mathcal {T}(G, \{v_0\})$ branches at $T_0$ into the leaf $T_R$ (containing $e$) and a chain $T_L \to T_{LL} \to T_{LLL}$ (the highlighted sub-tree). $(b)$ The disk $G_{T_L}$ inside the seam $C_{T_L}$, drawn standalone with $C_{T_L}$ as cycle source and vertex labels rotated to match the new (cycle-source) role of the boundary triangle. $\ell _{G_{T_L}}(\cdot ) = \ell _G(\cdot ) - 1$ on $V(G_{T_L})$ (verified by the generator script), and $\mathcal {T}(G_{T_L}, C_{T_L})$ is the chain $T_L \to T_{LL} \to T_{LLL}$, iso to the highlighted sub-tree of $(a)$.}}{14}{}\protected@file@percent }
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\@writefile{lof}{\contentsline {figure}{\numberline {4}{\ignorespaces Case 2 ($R$ = annulus) with $O$ a barbell. $B_{\mathrm {out}}$ is the outer hexagon (red); $O$ has two triangles $\{a_1, a_2, a_3\}$ and $\{b_1, b_2, b_3\}$ joined by the bridge $a_3\text {--}b_1$ (all light red). The annulus is triangulated by $14$ annular triangles: $6$ ``outer-cap'' triangles (one per outer edge), $6$ ``inner-cap'' triangles (one per non-bridge edge of $O$), and $2$ ``bridge-cap'' triangles $\{u_0, a_3, b_1\}$ and $\{u_3, a_3, b_1\}$ adjacent to the bridge. Each blue dot sits at the centroid of an annular triangle; blue edges connect dual vertices whose triangles share an interior annular edge (spoke or bridge). The two bridge-cap vertices have $\Gamma $-degree $3$ (their triangles have no boundary edge) and are joined by the dashed blue \emph {chord} corresponding to the bridge; the remaining $13$ edges form the Hamilton cycle that wraps around the annulus. All $14$ vertices lie on the outer face of the cycle-with-chord embedding, so $\Gamma \cong \Theta (1, 7, 7)$ is outerplanar.}}{10}{}\protected@file@percent }
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\@writefile{lof}{\contentsline {figure}{\numberline {5}{\ignorespaces Tire-tree decomposition (Theorem\nonbreakingspace 1.20\hbox {}) on a $13$-vertex maximal planar example $G$ with five BFS levels. $(a)$ $G$ with vertex source $v_0$ and $\ell _G \in \{0,1,2,3,4\}$; four nested seams are highlighted, $C_{T_R} = \{a,b,c\}$ (orange), $C_{T_L} = \{a,c,d\}$ (red, including the chord $a$-$c$ shared with $C_{T_R}$), $C_{T_{LL}} = \{f_1, f_2, f_3\}$ (purple), $C_{T_{LLL}} = \{g_1, g_2, g_3\}$ (teal). Inset: the rooted tree of tire treads $\mathcal {T}(G, \{v_0\})$ branches at $T_0$ into the leaf $T_R$ (containing $e$) and a chain $T_L \to T_{LL} \to T_{LLL}$ (the highlighted sub-tree). $(b)$ The disk $G_{T_L}$ inside the seam $C_{T_L}$, drawn standalone with $C_{T_L}$ as cycle source and vertex labels rotated to match the new (cycle-source) role of the boundary triangle. $\ell _{G_{T_L}}(\cdot ) = \ell _G(\cdot ) - 1$ on $V(G_{T_L})$ (verified by the generator script), and $\mathcal {T}(G_{T_L}, C_{T_L})$ is the chain $T_L \to T_{LL} \to T_{LLL}$, iso to the highlighted sub-tree of $(a)$.}}{15}{}\protected@file@percent }
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\bibcite{tait-original}{1}
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texlive/2022/texmf-dist/fonts/type1/public/amsfonts/cm/cmsy10.pfb></usr/local/t
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exlive/2022/texmf-dist/fonts/type1/public/amsfonts/cm/cmsy5.pfb></usr/local/tex
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live/2022/texmf-dist/fonts/type1/public/amsfonts/cm/cmsy6.pfb></usr/local/texli
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ve/2022/texmf-dist/fonts/type1/public/amsfonts/cm/cmsy7.pfb></usr/local/texlive
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/2022/texmf-dist/fonts/type1/public/amsfonts/cm/cmsy9.pfb></usr/local/texlive/2
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022/texmf-dist/fonts/type1/public/amsfonts/cm/cmti10.pfb></usr/local/texlive/20
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22/texmf-dist/fonts/type1/public/amsfonts/cm/cmti8.pfb></usr/local/texlive/2022
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/texmf-dist/fonts/type1/public/amsfonts/symbols/msam10.pfb></usr/local/texlive/
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2022/texmf-dist/fonts/type1/public/amsfonts/symbols/msbm10.pfb>
|
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Output written on paper.pdf (16 pages, 929392 bytes).
|
||||
PDF statistics:
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192 PDF objects out of 1000 (max. 8388607)
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116 compressed objects within 2 object streams
|
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|
||||
Binary file not shown.
@@ -98,7 +98,10 @@ A \emph{level source} of $G$ is a set $S \subseteq V$ that is either
|
||||
\begin{definition}[Levels]
|
||||
Given a level source $S \subseteq V$, the \emph{level} of $v \in V$ is
|
||||
$\ell_G(v) = \mathrm{dist}_G(v, S)$, the graph distance from $v$ to the nearest
|
||||
source vertex.
|
||||
source vertex. We write $L_d := \{v \in V : \ell_G(v) = d\}$ for the
|
||||
\emph{level-$d$ vertex set}, and abbreviate $L_{<d} := \bigcup_{d' < d}
|
||||
L_{d'}$ and $L_{\geq d} := \bigcup_{d' \geq d} L_{d'}$ (similarly
|
||||
$L_{>d}$, $L_{\leq d}$).
|
||||
\end{definition}
|
||||
|
||||
\begin{definition}[Dual]
|
||||
@@ -136,6 +139,23 @@ vertex.}
|
||||
\label{fig:dual-depth}
|
||||
\end{figure}
|
||||
|
||||
\begin{definition}[Depth-$d$ dual subgraph and its components]
|
||||
\label{def:dual-component}
|
||||
For $d \geq 0$, the \emph{depth-$d$ dual subgraph} is
|
||||
\[
|
||||
G'_d \;:=\; G'\bigl[\,\{d_f \in V(G') : \delta_G(d_f) = d\}\,\bigr],
|
||||
\]
|
||||
the inner-dual subgraph induced on the dual vertices of dual depth $d$.
|
||||
For a connected component $C'$ of $G'_d$ we write
|
||||
\[
|
||||
F_{C'} := \{f : d_f \in V(C')\}, \qquad
|
||||
V_{C'} := \bigcup_{f \in F_{C'}} V(f),
|
||||
\]
|
||||
for its set of faces and the vertices of $G$ bounding them, and
|
||||
$R_{C'} := \bigcup_{f \in F_{C'}} f \subseteq |\Pi_G|$ for the closed
|
||||
planar region these faces cover.
|
||||
\end{definition}
|
||||
|
||||
\begin{definition}[Tire graph]
|
||||
\label{def:tire-graph}
|
||||
A \emph{tire graph} consists of a plane graph $T$ together with an
|
||||
@@ -164,7 +184,9 @@ where $E_{\mathrm{ann}}$ --- the \emph{annular edges} --- has the
|
||||
property that, in the plane embedding of $T$, the closed planar
|
||||
region $R$ bounded externally by $B_{\mathrm{out}}$ and internally
|
||||
by $B_{\mathrm{in}}$ is partitioned into triangular faces of $T$
|
||||
whose union is $R$. We call $R$ the \emph{tire tread} of $T$.
|
||||
whose union is $R$. We call $R$ the \emph{tire tread} of $T$ and write
|
||||
$F_{\mathrm{ann}}$ for this set of triangular faces (the \emph{annular
|
||||
faces}).
|
||||
|
||||
When $B_{\mathrm{out}}$ is a simple cycle and $O$ is $2$-connected,
|
||||
the tread is a closed annulus. More generally, $R$ is a closed
|
||||
@@ -176,6 +198,11 @@ definition accommodates outerplanar inner graphs with bridges,
|
||||
cut-vertices, or multiple connected components. When either
|
||||
boundary is degenerate, the tread is a closed disk with that vertex
|
||||
as apex.
|
||||
|
||||
We summarize the data of a tire graph as the triple
|
||||
$T = (B_{\mathrm{out}}, O, E_{\mathrm{ann}})$, from which $B_{\mathrm{in}}$,
|
||||
the annular faces $F_{\mathrm{ann}}$, and the tread $R$ are determined;
|
||||
we freely identify a tire graph with its underlying plane graph $T$.
|
||||
\end{definition}
|
||||
|
||||
\begin{figure}[h]
|
||||
@@ -193,12 +220,12 @@ triangular faces.}
|
||||
|
||||
\begin{remark}
|
||||
\label{rem:tire-counts}
|
||||
Let $m = |V(B_{\mathrm{out}})|$ and $k = |V(B_{\mathrm{in}})|$. By
|
||||
Euler's formula on the tire tread $R$, the tire graph has $m + k$
|
||||
triangular faces inside $R$ and $|E_{\mathrm{ann}}| = m + k$
|
||||
Let $\mu = |V(B_{\mathrm{out}})|$ and $\nu = |V(B_{\mathrm{in}})|$. By
|
||||
Euler's formula on the tire tread $R$, the tire graph has $\mu + \nu$
|
||||
triangular faces inside $R$ and $|E_{\mathrm{ann}}| = \mu + \nu$
|
||||
annular edges when neither boundary is degenerate; when exactly one
|
||||
boundary is degenerate (so $\min(m, k) = 1$), there are $m + k - 1$
|
||||
triangular faces and $|E_{\mathrm{ann}}| = m + k - 1$.
|
||||
boundary is degenerate (so $\min(\mu, \nu) = 1$), there are $\mu + \nu - 1$
|
||||
triangular faces and $|E_{\mathrm{ann}}| = \mu + \nu - 1$.
|
||||
\end{remark}
|
||||
|
||||
\begin{proposition}[Source-side simple-cycle property]
|
||||
@@ -268,16 +295,11 @@ contradicting the conclusion that the entire path lies on one side.
|
||||
Let $G$ be a maximal planar graph and let $S \subseteq V(G)$ be a level
|
||||
source. Fix a plane embedding $\Pi_G$ of $G$ in which $S$ lies on the
|
||||
outer face (such an embedding exists for any planar graph and any
|
||||
single-vertex source). For $d \geq 0$, let
|
||||
\[
|
||||
G'_d \;:=\; G'\bigl[\,\{d_f \in V(G') : \delta_G(d_f) = d\}\,\bigr]
|
||||
\]
|
||||
be the inner-dual subgraph on dual vertices of dual depth $d$, and let
|
||||
$C'$ be a connected component of $G'_d$. Write
|
||||
$F_{C'} := \{f : d_f \in V(C')\}$,
|
||||
$V_{C'} := \bigcup_{f \in F_{C'}} V(f)$, and let $C := G[V_{C'}]$ inherit
|
||||
its embedding from $\Pi_G$. Set $R_{C'} := \bigcup_{f \in F_{C'}} f
|
||||
\subseteq |\Pi_G|$.
|
||||
single-vertex source). For $d \geq 0$, let $C'$ be a connected
|
||||
component of the depth-$d$ dual subgraph $G'_d$, with faces $F_{C'}$,
|
||||
bounding vertices $V_{C'}$, and region $R_{C'}$ as in
|
||||
Definition~\ref{def:dual-component}; let $C := G[V_{C'}]$ inherit its
|
||||
embedding from $\Pi_G$.
|
||||
|
||||
Then $C$, with the inherited embedding, is a tire graph in the sense of Definition~\ref{def:tire-graph}. Its outer boundary
|
||||
$B_{\mathrm{out}}$ is the side of $R_{C'}$ closer to $S$ in $\Pi_G$,
|
||||
@@ -478,8 +500,11 @@ Let $T = (B_{\mathrm{out}}, O, E_{\mathrm{ann}})$ be a tire graph,
|
||||
and let $\Gamma$ be the graph on vertex set
|
||||
$\{d_f : f \in F_{\mathrm{ann}}\}$ with an edge $d_f d_{f'}$ for
|
||||
each interior annular edge of $T$ (= each edge of $T$ whose two
|
||||
incident faces both lie in $F_{\mathrm{ann}}$). Then $\Gamma$ is
|
||||
outerplanar.
|
||||
incident faces both lie in $F_{\mathrm{ann}}$). Equivalently,
|
||||
$\Gamma$ is the subgraph induced on $F_{\mathrm{ann}}$ of the
|
||||
\emph{full tire dual} $D(T)$ --- the dual of $T$ taken over all of
|
||||
its triangular faces, in which each boundary edge of $R$ contributes
|
||||
a degree-$1$ vertex. Then $\Gamma$ is outerplanar.
|
||||
|
||||
Moreover, $\Gamma$ admits a planar embedding as a (possibly
|
||||
non-simple) Hamilton walk through every $d_f$, plus zero or more
|
||||
@@ -569,12 +594,12 @@ $\partial R = B_{\mathrm{out}} \sqcup \overline{B_{\mathrm{in}}}$
|
||||
appropriate orientation). Each boundary edge of $R$ is incident to
|
||||
exactly one annular face: walking around $B_{\mathrm{out}}$ in
|
||||
cyclic order produces a sequence
|
||||
$f^{\mathrm{out}}_1, f^{\mathrm{out}}_2, \dots, f^{\mathrm{out}}_n$
|
||||
$f^{\mathrm{out}}_1, f^{\mathrm{out}}_2, \dots, f^{\mathrm{out}}_\mu$
|
||||
of (not necessarily distinct) annular faces, one per
|
||||
$B_{\mathrm{out}}$-edge; similarly walking around
|
||||
$B_{\mathrm{in}}$ produces a sequence
|
||||
$f^{\mathrm{in}}_1, \dots, f^{\mathrm{in}}_{m_\partial}$ where
|
||||
$m_\partial$ is the length of the inner-boundary walk. Pick any
|
||||
$f^{\mathrm{in}}_1, \dots, f^{\mathrm{in}}_{\nu_\partial}$ where
|
||||
$\nu_\partial$ is the length of the inner-boundary walk. Pick any
|
||||
spoke $e^\star = u w \in E_{\mathrm{ann}}$ with $u \in
|
||||
V(B_{\mathrm{out}})$ and $w \in V(B_{\mathrm{in}})$; cut $R$ along
|
||||
$e^\star$. This converts the annulus into a closed disk
|
||||
@@ -584,8 +609,8 @@ and once back along $e^\star$. Concatenating the two boundary
|
||||
sequences (in the order dictated by this disk traversal) yields a
|
||||
single cyclic sequence
|
||||
\[
|
||||
\mathcal{S} = (f^{\mathrm{out}}_1, \dots, f^{\mathrm{out}}_n,
|
||||
f^{\mathrm{in}}_1, \dots, f^{\mathrm{in}}_{m_\partial})
|
||||
\mathcal{S} = (f^{\mathrm{out}}_1, \dots, f^{\mathrm{out}}_\mu,
|
||||
f^{\mathrm{in}}_1, \dots, f^{\mathrm{in}}_{\nu_\partial})
|
||||
\]
|
||||
of annular faces with multiplicities.
|
||||
|
||||
@@ -742,7 +767,7 @@ $O$ $2$-connected and $E_{\mathrm{ann}}$ consisting only of spokes),
|
||||
every annular face has exactly one boundary edge, every
|
||||
$d_f$ has $\Gamma$-degree $2$, and the construction of the
|
||||
Theorem~\ref{thm:inner-dual-outerplanar} proof reduces to the
|
||||
classical Hamilton cycle $\Gamma \cong C_{n+m}$ with zero chords.
|
||||
classical Hamilton cycle $\Gamma \cong C_{\mu+\nu}$ with zero chords.
|
||||
\end{remark}
|
||||
|
||||
\begin{remark}
|
||||
@@ -753,7 +778,7 @@ an interior annular edge in $\Gamma$ rather than two leaves in
|
||||
$D(T)$ (see Definition~1.7 of \cite{bauerfeld-nested-tire-duals}).
|
||||
The two bridge-incident annular triangles have $\Gamma$-degree $3$;
|
||||
the resulting $\Gamma$ has the structure of a Hamilton cycle of
|
||||
length $n + m_\partial$ plus a single chord (length $1$). This
|
||||
length $\mu + \nu_\partial$ plus a single chord (length $1$). This
|
||||
corresponds to the theta graph $\Theta(1, b, c)$ identified
|
||||
empirically in \cite{bauerfeld-nested-tire-duals}, which has no
|
||||
$K_{2,3}$ subdivision (since one of the three paths has length $1$
|
||||
@@ -823,13 +848,14 @@ stated equality.
|
||||
\label{rem:count-general-outerplanar}
|
||||
Theorem~\ref{thm:tait-tire} reduces the $4$-colouring count of a
|
||||
tire to the $3$-edge-coloring count of its outerplanar inner dual
|
||||
$\Gamma$. For the cycle case $\Gamma \cong C_n$ (the spoke-only
|
||||
$\Gamma$. For the cycle case $\Gamma \cong C_{\mu+\nu}$ (the spoke-only
|
||||
case of Remark~\ref{rem:hamilton-cycle-spoke-only}), the cycle
|
||||
chromatic polynomial at $k = 3$ gives
|
||||
$2^n + 2 (-1)^n$. For an inner dual with one or more non-crossing
|
||||
chords, the count depends on the chord structure, not just on the
|
||||
pair (number of vertices, number of chords): two outerplanar graphs
|
||||
with the same $n$ and number of chords can have different proper
|
||||
chromatic polynomial at $3$ colours gives
|
||||
$2^{\mu+\nu} + 2 (-1)^{\mu+\nu}$. For an inner dual with one or more
|
||||
non-crossing chords, the count depends on the chord structure, not just
|
||||
on the pair (number of vertices, number of chords): two outerplanar
|
||||
graphs with the same number of vertices and number of chords can have
|
||||
different proper
|
||||
$3$-edge-coloring counts depending on how the chords are arranged
|
||||
(nested, sequential, sharing vertices, etc.). Every such count
|
||||
can nevertheless be computed in linear time by tree-decomposition
|
||||
@@ -851,23 +877,23 @@ tree structure $\mathcal{T}(G, S)$ defined as follows.
|
||||
\item \emph{Root.} The depth-$0$ tire tread $T_0$ --- the unique
|
||||
tire produced by Lemma~\ref{lem:tire-component} at $d = 0$,
|
||||
with degenerate outer boundary $B_{\mathrm{out}} = \{v_0\}$
|
||||
and inner outerplanar graph $O^{(0)} = G[L_1]$ --- is the
|
||||
and inner outerplanar graph $O^{(T_0)} = G[L_1]$ --- is the
|
||||
root.
|
||||
\item \emph{Parent.} For each tire tread $T_c$ at depth $d \ge 1$,
|
||||
its outer boundary $B_{\mathrm{out}}^{(c)}$ is a cycle in
|
||||
its outer boundary $B_{\mathrm{out}}^{(T_c)}$ is a cycle in
|
||||
$L_d$. The \emph{parent} of $T_c$ is the unique tire tread
|
||||
$T_p$ at depth $d - 1$ whose inner outerplanar graph
|
||||
$O^{(p)}$ has $B_{\mathrm{out}}^{(c)}$ as the boundary cycle
|
||||
$O^{(T_p)}$ has $B_{\mathrm{out}}^{(T_c)}$ as the boundary cycle
|
||||
of one of its bounded faces. Equivalently, $R_c$ lies
|
||||
inside this bounded face of $O^{(p)}$ (which is itself the
|
||||
region of the plane cut off by $B_{\mathrm{out}}^{(c)}$ on
|
||||
inside this bounded face of $O^{(T_p)}$ (which is itself the
|
||||
region of the plane cut off by $B_{\mathrm{out}}^{(T_c)}$ on
|
||||
the side away from $S$).
|
||||
\item \emph{Children.} The children of a tire tread $T_p$ are in
|
||||
bijection with those bounded faces of $O^{(p)}$ whose
|
||||
bijection with those bounded faces of $O^{(T_p)}$ whose
|
||||
interiors contain at least one vertex of $G$ at level
|
||||
$\ge d + 2$ --- equivalently, with the connected components
|
||||
of $G'_{d+1}$ whose tires have outer boundary cycle equal to
|
||||
a bounded face of $O^{(p)}$.
|
||||
a bounded face of $O^{(T_p)}$.
|
||||
\end{itemize}
|
||||
|
||||
Every tire tread except $T_0$ has exactly one parent; a tire
|
||||
@@ -884,34 +910,34 @@ gives the depth-$0$ tire $T_0$ described above.
|
||||
|
||||
\emph{Existence of parent.} Fix a tire tread $T_c$ at depth $d
|
||||
\ge 1$ arising from a connected component $C'_c$ of $G'_d$. Its
|
||||
outer boundary $B_{\mathrm{out}}^{(c)} = G[V_{C'_c} \cap L_d]$ is
|
||||
outer boundary $B_{\mathrm{out}}^{(T_c)} = G[V_{C'_c} \cap L_d]$ is
|
||||
a simple cycle in $L_d$ (Lemma~\ref{lem:tire-component}; the
|
||||
source-side boundary of a tire is always a simple cycle, by
|
||||
Proposition~\ref{prop:no-level-d-pinch}). The faces of $G$
|
||||
immediately outside $B_{\mathrm{out}}^{(c)}$ on the side facing $S$
|
||||
immediately outside $B_{\mathrm{out}}^{(T_c)}$ on the side facing $S$
|
||||
have depth $d - 1$ (one of their three vertices lies in $L_{d-1}$,
|
||||
two in $L_d$). Let $C'_p$ be the connected component of
|
||||
$G'_{d-1}$ containing the dual vertex of any such face.
|
||||
|
||||
\emph{Uniqueness of parent.} $B_{\mathrm{out}}^{(c)}$ is a single
|
||||
\emph{Uniqueness of parent.} $B_{\mathrm{out}}^{(T_c)}$ is a single
|
||||
simple cycle in $G$, with a well-defined ``$S$-side'' (the side
|
||||
of the cycle closer to $v_0$ in $\Pi_G$). The depth-$(d-1)$
|
||||
faces lying on this side form a single contiguous arc around
|
||||
$B_{\mathrm{out}}^{(c)}$ in the dual --- they are all $G'$-adjacent
|
||||
$B_{\mathrm{out}}^{(T_c)}$ in the dual --- they are all $G'$-adjacent
|
||||
in sequence (each pair of consecutive arc faces shares an edge in
|
||||
$B_{\mathrm{out}}^{(c)}$). Hence they all lie in the same
|
||||
$B_{\mathrm{out}}^{(T_c)}$). Hence they all lie in the same
|
||||
connected component $C'_p$ of $G'_{d-1}$, which is therefore
|
||||
unique.
|
||||
|
||||
\emph{$B_{\mathrm{out}}^{(c)}$ bounds a face of $O^{(p)}$.} The
|
||||
parent tire $T_p$ has $V(O^{(p)}) = V_{C'_p} \cap L_d \supseteq
|
||||
V(B_{\mathrm{out}}^{(c)})$. The cycle $B_{\mathrm{out}}^{(c)}$ is
|
||||
a subgraph of $O^{(p)}$ that bounds a face of $O^{(p)}$ in the
|
||||
\emph{$B_{\mathrm{out}}^{(T_c)}$ bounds a face of $O^{(T_p)}$.} The
|
||||
parent tire $T_p$ has $V(O^{(T_p)}) = V_{C'_p} \cap L_d \supseteq
|
||||
V(B_{\mathrm{out}}^{(T_c)})$. The cycle $B_{\mathrm{out}}^{(T_c)}$ is
|
||||
a subgraph of $O^{(T_p)}$ that bounds a face of $O^{(T_p)}$ in the
|
||||
inherited embedding: the cycle traces around a depth-$\ge d+1$
|
||||
region (containing $R_c$ and any descendants of $T_c$), which is
|
||||
exactly a bounded face of $O^{(p)}$.
|
||||
exactly a bounded face of $O^{(T_p)}$.
|
||||
|
||||
\emph{Children description.} The bounded faces of $O^{(p)}$ are
|
||||
\emph{Children description.} The bounded faces of $O^{(T_p)}$ are
|
||||
in bijection with the connected components of $G'_d$ whose
|
||||
faces lie inside those bounded regions (= one component per
|
||||
bounded face, by an argument analogous to the existence-and-
|
||||
@@ -926,12 +952,12 @@ decreases depth, terminating at $T_0$. No cycles can form
|
||||
\begin{remark}
|
||||
\label{rem:tree-multiple-children}
|
||||
A parent tire $T_p$ has multiple children precisely when its
|
||||
inner outerplanar graph $O^{(p)}$ has multiple bounded faces with
|
||||
inner outerplanar graph $O^{(T_p)}$ has multiple bounded faces with
|
||||
non-trivial interiors (= containing depth-$\ge d+2$ vertices of
|
||||
$G$). This happens, for instance, when $O^{(p)}$ has chords or
|
||||
cut-vertices that subdivide its inner region, or when $O^{(p)}$
|
||||
$G$). This happens, for instance, when $O^{(T_p)}$ has chords or
|
||||
cut-vertices that subdivide its inner region, or when $O^{(T_p)}$
|
||||
has multiple connected components in $G[L_{d+1}] \cap V_{C'_p}$.
|
||||
By contrast, if $O^{(p)}$ is a simple cycle (the spoke-only case
|
||||
By contrast, if $O^{(T_p)}$ is a simple cycle (the spoke-only case
|
||||
of Remark~\ref{rem:hamilton-cycle-spoke-only}) with a non-empty
|
||||
interior, $T_p$ has exactly one child.
|
||||
\end{remark}
|
||||
@@ -1127,8 +1153,8 @@ proper coloring problem on $G$'s bounded faces factors through:
|
||||
each tread is outerplanar by
|
||||
Theorem~\ref{thm:inner-dual-outerplanar}), plus
|
||||
\item consistency constraints along parent-child interfaces (the
|
||||
cycle $B_{\mathrm{out}}^{(c)}$ shared between a child and the
|
||||
face of its parent's $O^{(p)}$).
|
||||
cycle $B_{\mathrm{out}}^{(T_c)}$ shared between a child and the
|
||||
face of its parent's $O^{(T_p)}$).
|
||||
\end{itemize}
|
||||
This is the structural setup underlying the chain-pigeonhole
|
||||
program for tire treads.
|
||||
|
||||
Reference in New Issue
Block a user