Restate conjecture with "bridge-derived"; update empirical table and n=21
- Conjecture now reads "bridge-derived level graph ... an intertwining tree,
or both" -- the stronger form the evidence actually supports (a bridge-
derived level graph is automatically a valid derived level graph).
- Empirical table recomputed for bridge-derivability, exhaustively for n<=9
(every backward bridge-orbit fully enumerable there):
n=7: 1 inter-only; n=8: 2 inter-only; n=9: 14 inter-only; missing=0.
Added prose: below n=21 every class is intertwining, so the table shows
how far the bridge-derived disjunct reaches on its own (36/50 at n=9) and
that the two disjuncts complement each other; "bridge only" is 0 in range.
- n=21 subsection notes the four witnesses are explicit, short (path lengths
3,1,2,4), archived, and step-verified.
Co-Authored-By: Claude Opus 4.7 <noreply@anthropic.com>
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"""Recompute the empirical table for the bridge-derived disjunction:
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for each n, count iso classes that are bridge-derived only / intertwining
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only / both / neither (missing)."""
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import sys
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import os
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sys.path.insert(0, '/Users/didericis/Code/math-research/papers/'
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'level_resolutions_of_maximal_planar_graphs/experiments')
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sys.path.insert(0, os.path.dirname(os.path.abspath(__file__)))
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from triangulation_gen import enumerate_all_triangulations
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from small_n_probe import is_bridge_derived
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from test_disjunction import is_intertwining_tree
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def main(ns):
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print('n iso bridge_only inter_only both missing', flush=True)
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for n in ns:
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tris = enumerate_all_triangulations(n)
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bo = io = both = miss = 0
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for G in tris:
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bd = is_bridge_derived(G)
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it = is_intertwining_tree(G)
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if isinstance(it, tuple):
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it = it[0]
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if bd and it:
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both += 1
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elif bd:
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bo += 1
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elif it:
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io += 1
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else:
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miss += 1
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print(f'{n} {len(tris)} {bo} {io} {both} {miss}', flush=True)
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if __name__ == '__main__':
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ns = [int(x) for x in sys.argv[1:]] or [6, 7, 8, 9, 10, 11, 12]
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main(ns)
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