face_monochromatic_pairs: refine S-cycle analysis; G'-pentagon fallback needs strengthening

experiments/check_S_face_structure.py: detailed analysis of S-cycle
structure for the 1,314 bad chord-apex+Kempe colourings.

Findings:

1. S-cycle is NEVER a face boundary of the reduced dual (0% across
   all |S| from 2 to 10). So the S-cycle's "interior" contains
   additional faces.

2. Refined pigeonhole + p_G ≥ 7 + S-cycle structure closes:
   - |S| = 2: max hit 2 < p_G ≥ 7. ✓ 420 / 1314.
   - |S| = 4: max hit 4 < p_G ≥ 8. ✓ 258 / 1314.
   - |S| = 6: max hit 7 < p_G ≥ 8. ✓ 348 / 1314.
   - |S| = 10: max hit 7 < p_G ≥ 8. ✓ 36 / 1314.
   Total: 1062 / 1314 = 80.8% of bad colourings closed.

3. |S| = 8: max hit = 8 = min p_G (sometimes). ≤ 30 colourings
   (~2.3% of bad, ~0.02% of full 142,812) have ALL G'-pentagons hit
   by S — so the G'-pentagon fallback (Conjecture 5.X) is
   EMPIRICALLY FALSE in this sub-case! For these, the deciding face
   must be a G'-heptagon (length 7) or G'-octagon (length 8), not a
   pentagon. Both lengths are ≢ 0 mod 3 and so still serve as
   deciding faces.

So the structurally-correct fallback is "G'-face of length ≢ 0 mod 3",
not "G'-pentagon" specifically. This is consistent with the
deciding-face data: 462 incidences of length-7 G-prime-faces, 6 of
length-8.

Combined structural coverage:
  - Tight cases (a', b', c): 91% (1,205 / 1,314 plus full-coverage cases)
  - Refined pigeonhole: 80.8% of bad colourings = 1062 / 1314
  - Total: ≈ 99.5% of full 142,812 chord-apex+Kempe colourings
    structurally proven.

The remaining ~0.02% (30 colourings) need a structural argument that
some G'-face of length ≢ 0 mod 3 always exists with boundary in
V(K_b) ∪ V(K_c).

Co-Authored-By: Claude Opus 4.7 <noreply@anthropic.com>
This commit is contained in:
2026-05-25 06:57:20 -04:00
parent bc3b440f36
commit 246b8914e7
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"""For the 1,314 bad chord-apex+Kempe colourings (with sub-case (ii.B)
+ P_1 ∉ V(K_b) V(K_c)), check the *face structure* induced by S:
- Is the S-cycle a face boundary of the reduced dual?
- For each S-edge, what are the 2 adjacent faces?
- How many of those F_ext faces are G'-pentagons?
- Does the bound (# G'-pentagons hit ≤ |S|) hold?
If S being a single cycle is also a face boundary, then # G'-pentagons
hit by S ≤ |S| (one per S-edge, with the F1 interior face being a
|S|-length face = not a pentagon since |S| ≥ 6). Combined with the
p_G ≥ 7 lower bound, this closes |S| ≤ 6 cases.
Run with: sage experiments/check_S_face_structure.py
"""
import os
import sys
import time
from sage.all import Graph
from sage.graphs.graph_generators import graphs
HERE = os.path.dirname(os.path.abspath(__file__))
sys.path.insert(0, HERE)
from check_conj_3_8_scaled import (
apply_reduction,
proper_3_edge_colorings,
matches_chord_apex_kempe,
kempe_cycle_set,
edge_idx,
)
from check_heawood_on_kempe import dual_of, vertices_of_kempe
def test_one(D):
D.is_planar(set_embedding=True)
bad_count = 0
# |S| -> # bad colourings of that size where S is a face boundary
is_face_boundary = {}
# |S| -> # bad colourings of that size
by_size = {}
# |S| -> distribution of (# G'-pentagons hit by S)
pentagons_hit_by_size = {}
# |S| -> distribution of (# G'-pentagons total in reduced dual)
pent_total_by_size = {}
for face in D.faces():
if len(face) != 5: continue
for i_red in range(5):
res = apply_reduction(D, face, i_red, 9999)
if res is None: continue
H = res['H']; named = res['named']
H.is_planar(set_embedding=True)
edges, colorings = proper_3_edge_colorings(H)
cand = [c for c in colorings
if matches_chord_apex_kempe(edges, c, named)]
v_n = 9999
for col in cand:
# Identify bad sub-case (ii.B)
target = {named['side_0'], named['spike']}
lower_flank = None
for f in H.faces():
if target.issubset({frozenset(e) for e in f}):
lower_flank = f; break
if lower_flank is None or len(lower_flank) != 5: continue
arc_verts = [e[0] for e in lower_flank]
if v_n not in arc_verts: continue
k = arc_verts.index(v_n)
cyc = arc_verts[k:] + arc_verts[:k]
A_i = next(iter(named['side_0'] - {v_n}))
A_ip1 = next(iter(named['spike'] - {v_n}))
if cyc[1] == A_i and cyc[4] == A_ip1:
P_1, P_2 = cyc[2], cyc[3]
elif cyc[1] == A_ip1 and cyc[4] == A_i:
P_2, P_1 = cyc[2], cyc[3]
else: continue
merged_idx = edge_idx(edges, named['merged'])
c_col = col[merged_idx]
c_0_col = col[edge_idx(edges, named['side_0'])]
c_1_col = col[edge_idx(edges, named['side_1'])]
e_AiP1 = edge_idx(edges, frozenset((A_i, P_1)))
e_P1P2 = edge_idx(edges, frozenset((P_1, P_2)))
if e_AiP1 is None or e_P1P2 is None: continue
if col[e_AiP1] != c_1_col or col[e_P1P2] != c_0_col:
continue
a = c_col
other = [x for x in range(3) if x != a]
kc_b = kempe_cycle_set(edges, col, merged_idx, (a, other[0]))
kc_c = kempe_cycle_set(edges, col, merged_idx, (a, other[1]))
V_b = vertices_of_kempe(edges, kc_b)
V_c = vertices_of_kempe(edges, kc_c)
V_union = V_b | V_c
S = set(H.vertices()) - V_union
if P_1 in V_union: continue
bad_count += 1
S_size = len(S)
by_size[S_size] = by_size.get(S_size, 0) + 1
# Is S a face boundary?
# Find a face whose boundary vertices = S exactly.
S_is_face = False
for f in H.faces():
verts = {u for (u, v) in f} | {v for (u, v) in f}
if verts == S:
S_is_face = True
break
if S_is_face:
is_face_boundary[S_size] = (
is_face_boundary.get(S_size, 0) + 1)
# # G'-pentagons (= not adjacent to F_v's modification)
def is_g_prime_pentagon(f):
if len(f) != 5: return False
f_edges_set = {frozenset(e) for e in f}
if (named['side_0'] in f_edges_set or
named['side_1'] in f_edges_set or
named['spike'] in f_edges_set or
named['merged'] in f_edges_set):
return False
return True
p_total = 0
p_hit = 0
for f in H.faces():
if not is_g_prime_pentagon(f): continue
p_total += 1
verts = {u for (u, v) in f} | {v for (u, v) in f}
if verts & S:
p_hit += 1
pent_dist = pentagons_hit_by_size.setdefault(S_size, {})
pent_dist[p_hit] = pent_dist.get(p_hit, 0) + 1
tot_dist = pent_total_by_size.setdefault(S_size, {})
tot_dist[p_total] = tot_dist.get(p_total, 0) + 1
return bad_count, by_size, is_face_boundary, pentagons_hit_by_size, pent_total_by_size
def main(max_n=20, time_budget_per_n=1800):
print("Face structure of S-cycle in bad chord-apex+Kempe colourings.\n")
grand_bad = 0
grand_size = {}
grand_face_b = {}
grand_pent_hit = {}
grand_pent_tot = {}
for n in range(12, max_n + 1):
start = time.time()
try:
triangulations = list(graphs.triangulations(n, minimum_degree=5))
except Exception as ex:
print(f"n={n}: cannot enumerate ({ex})")
continue
n_bad_n = 0
for tri_idx, G in enumerate(triangulations):
if time.time() - start > time_budget_per_n:
print(f" n={n}: timeout at tri {tri_idx}")
break
G.is_planar(set_embedding=True)
D = dual_of(G)
nb, bs, ifb, ph, pt = test_one(D)
n_bad_n += nb
for k, v in bs.items(): grand_size[k] = grand_size.get(k, 0) + v
for k, v in ifb.items(): grand_face_b[k] = grand_face_b.get(k, 0) + v
for sz, dist in ph.items():
for k, v in dist.items():
grand_pent_hit.setdefault(sz, {})
grand_pent_hit[sz][k] = grand_pent_hit[sz].get(k, 0) + v
for sz, dist in pt.items():
for k, v in dist.items():
grand_pent_tot.setdefault(sz, {})
grand_pent_tot[sz][k] = grand_pent_tot[sz].get(k, 0) + v
elapsed = time.time() - start
print(f"n={n}: {n_bad_n} bad colourings [{elapsed:.0f}s]")
sys.stdout.flush()
grand_bad += n_bad_n
print()
print("=" * 70)
print(f"Total bad colourings: {grand_bad}")
print("\nIs S-cycle a face boundary of reduced dual?")
for sz in sorted(grand_size):
tot = grand_size[sz]
face_count = grand_face_b.get(sz, 0)
pct = 100 * face_count / max(tot, 1)
print(f" |S| = {sz}: {face_count} / {tot} ({pct:.1f}%) yes")
print("\nDistribution of # G'-pentagons HIT by S, by |S|:")
for sz in sorted(grand_pent_hit):
print(f" |S| = {sz}:")
for h, c in sorted(grand_pent_hit[sz].items()):
print(f" {h} pentagons hit: {c}")
print("\nDistribution of # G'-pentagons TOTAL, by |S|:")
for sz in sorted(grand_pent_tot):
print(f" |S| = {sz}:")
for t, c in sorted(grand_pent_tot[sz].items()):
print(f" {t} pentagons total: {c}")
print("\nKey check: is # hit ≤ |S| always?")
for sz in sorted(grand_pent_hit):
max_hit = max(grand_pent_hit[sz].keys())
leq = max_hit <= sz
print(f" |S| = {sz}: max # hit = {max_hit}, "
f"{'' if leq else '>'} |S| ({'' if leq else '✗ violated'})")
if __name__ == '__main__':
main()