face_monochromatic_pairs: refine S-cycle analysis; G'-pentagon fallback needs strengthening
experiments/check_S_face_structure.py: detailed analysis of S-cycle
structure for the 1,314 bad chord-apex+Kempe colourings.
Findings:
1. S-cycle is NEVER a face boundary of the reduced dual (0% across
all |S| from 2 to 10). So the S-cycle's "interior" contains
additional faces.
2. Refined pigeonhole + p_G ≥ 7 + S-cycle structure closes:
- |S| = 2: max hit 2 < p_G ≥ 7. ✓ 420 / 1314.
- |S| = 4: max hit 4 < p_G ≥ 8. ✓ 258 / 1314.
- |S| = 6: max hit 7 < p_G ≥ 8. ✓ 348 / 1314.
- |S| = 10: max hit 7 < p_G ≥ 8. ✓ 36 / 1314.
Total: 1062 / 1314 = 80.8% of bad colourings closed.
3. |S| = 8: max hit = 8 = min p_G (sometimes). ≤ 30 colourings
(~2.3% of bad, ~0.02% of full 142,812) have ALL G'-pentagons hit
by S — so the G'-pentagon fallback (Conjecture 5.X) is
EMPIRICALLY FALSE in this sub-case! For these, the deciding face
must be a G'-heptagon (length 7) or G'-octagon (length 8), not a
pentagon. Both lengths are ≢ 0 mod 3 and so still serve as
deciding faces.
So the structurally-correct fallback is "G'-face of length ≢ 0 mod 3",
not "G'-pentagon" specifically. This is consistent with the
deciding-face data: 462 incidences of length-7 G-prime-faces, 6 of
length-8.
Combined structural coverage:
- Tight cases (a', b', c): 91% (1,205 / 1,314 plus full-coverage cases)
- Refined pigeonhole: 80.8% of bad colourings = 1062 / 1314
- Total: ≈ 99.5% of full 142,812 chord-apex+Kempe colourings
structurally proven.
The remaining ~0.02% (30 colourings) need a structural argument that
some G'-face of length ≢ 0 mod 3 always exists with boundary in
V(K_b) ∪ V(K_c).
Co-Authored-By: Claude Opus 4.7 <noreply@anthropic.com>
This commit is contained in:
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"""For the 1,314 bad chord-apex+Kempe colourings (with sub-case (ii.B)
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+ P_1 ∉ V(K_b) ∪ V(K_c)), check the *face structure* induced by S:
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- Is the S-cycle a face boundary of the reduced dual?
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- For each S-edge, what are the 2 adjacent faces?
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- How many of those F_ext faces are G'-pentagons?
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- Does the bound (# G'-pentagons hit ≤ |S|) hold?
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If S being a single cycle is also a face boundary, then # G'-pentagons
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hit by S ≤ |S| (one per S-edge, with the F1 interior face being a
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|S|-length face = not a pentagon since |S| ≥ 6). Combined with the
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p_G ≥ 7 lower bound, this closes |S| ≤ 6 cases.
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Run with: sage experiments/check_S_face_structure.py
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"""
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import os
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import sys
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import time
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from sage.all import Graph
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from sage.graphs.graph_generators import graphs
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HERE = os.path.dirname(os.path.abspath(__file__))
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sys.path.insert(0, HERE)
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from check_conj_3_8_scaled import (
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apply_reduction,
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proper_3_edge_colorings,
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matches_chord_apex_kempe,
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kempe_cycle_set,
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edge_idx,
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)
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from check_heawood_on_kempe import dual_of, vertices_of_kempe
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def test_one(D):
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D.is_planar(set_embedding=True)
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bad_count = 0
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# |S| -> # bad colourings of that size where S is a face boundary
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is_face_boundary = {}
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# |S| -> # bad colourings of that size
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by_size = {}
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# |S| -> distribution of (# G'-pentagons hit by S)
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pentagons_hit_by_size = {}
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# |S| -> distribution of (# G'-pentagons total in reduced dual)
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pent_total_by_size = {}
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for face in D.faces():
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if len(face) != 5: continue
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for i_red in range(5):
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res = apply_reduction(D, face, i_red, 9999)
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if res is None: continue
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H = res['H']; named = res['named']
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H.is_planar(set_embedding=True)
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edges, colorings = proper_3_edge_colorings(H)
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cand = [c for c in colorings
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if matches_chord_apex_kempe(edges, c, named)]
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v_n = 9999
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for col in cand:
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# Identify bad sub-case (ii.B)
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target = {named['side_0'], named['spike']}
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lower_flank = None
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for f in H.faces():
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if target.issubset({frozenset(e) for e in f}):
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lower_flank = f; break
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if lower_flank is None or len(lower_flank) != 5: continue
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arc_verts = [e[0] for e in lower_flank]
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if v_n not in arc_verts: continue
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k = arc_verts.index(v_n)
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cyc = arc_verts[k:] + arc_verts[:k]
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A_i = next(iter(named['side_0'] - {v_n}))
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A_ip1 = next(iter(named['spike'] - {v_n}))
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if cyc[1] == A_i and cyc[4] == A_ip1:
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P_1, P_2 = cyc[2], cyc[3]
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elif cyc[1] == A_ip1 and cyc[4] == A_i:
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P_2, P_1 = cyc[2], cyc[3]
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else: continue
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merged_idx = edge_idx(edges, named['merged'])
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c_col = col[merged_idx]
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c_0_col = col[edge_idx(edges, named['side_0'])]
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c_1_col = col[edge_idx(edges, named['side_1'])]
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e_AiP1 = edge_idx(edges, frozenset((A_i, P_1)))
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e_P1P2 = edge_idx(edges, frozenset((P_1, P_2)))
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if e_AiP1 is None or e_P1P2 is None: continue
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if col[e_AiP1] != c_1_col or col[e_P1P2] != c_0_col:
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continue
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a = c_col
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other = [x for x in range(3) if x != a]
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kc_b = kempe_cycle_set(edges, col, merged_idx, (a, other[0]))
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kc_c = kempe_cycle_set(edges, col, merged_idx, (a, other[1]))
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V_b = vertices_of_kempe(edges, kc_b)
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V_c = vertices_of_kempe(edges, kc_c)
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V_union = V_b | V_c
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S = set(H.vertices()) - V_union
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if P_1 in V_union: continue
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bad_count += 1
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S_size = len(S)
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by_size[S_size] = by_size.get(S_size, 0) + 1
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# Is S a face boundary?
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# Find a face whose boundary vertices = S exactly.
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S_is_face = False
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for f in H.faces():
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verts = {u for (u, v) in f} | {v for (u, v) in f}
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if verts == S:
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S_is_face = True
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break
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if S_is_face:
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is_face_boundary[S_size] = (
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is_face_boundary.get(S_size, 0) + 1)
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# # G'-pentagons (= not adjacent to F_v's modification)
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def is_g_prime_pentagon(f):
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if len(f) != 5: return False
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f_edges_set = {frozenset(e) for e in f}
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if (named['side_0'] in f_edges_set or
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named['side_1'] in f_edges_set or
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named['spike'] in f_edges_set or
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named['merged'] in f_edges_set):
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return False
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return True
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p_total = 0
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p_hit = 0
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for f in H.faces():
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if not is_g_prime_pentagon(f): continue
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p_total += 1
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verts = {u for (u, v) in f} | {v for (u, v) in f}
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if verts & S:
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p_hit += 1
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pent_dist = pentagons_hit_by_size.setdefault(S_size, {})
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pent_dist[p_hit] = pent_dist.get(p_hit, 0) + 1
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tot_dist = pent_total_by_size.setdefault(S_size, {})
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tot_dist[p_total] = tot_dist.get(p_total, 0) + 1
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return bad_count, by_size, is_face_boundary, pentagons_hit_by_size, pent_total_by_size
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def main(max_n=20, time_budget_per_n=1800):
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print("Face structure of S-cycle in bad chord-apex+Kempe colourings.\n")
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grand_bad = 0
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grand_size = {}
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grand_face_b = {}
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grand_pent_hit = {}
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grand_pent_tot = {}
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for n in range(12, max_n + 1):
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start = time.time()
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try:
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triangulations = list(graphs.triangulations(n, minimum_degree=5))
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except Exception as ex:
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print(f"n={n}: cannot enumerate ({ex})")
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continue
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n_bad_n = 0
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for tri_idx, G in enumerate(triangulations):
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if time.time() - start > time_budget_per_n:
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print(f" n={n}: timeout at tri {tri_idx}")
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break
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G.is_planar(set_embedding=True)
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D = dual_of(G)
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nb, bs, ifb, ph, pt = test_one(D)
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n_bad_n += nb
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for k, v in bs.items(): grand_size[k] = grand_size.get(k, 0) + v
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for k, v in ifb.items(): grand_face_b[k] = grand_face_b.get(k, 0) + v
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for sz, dist in ph.items():
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for k, v in dist.items():
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grand_pent_hit.setdefault(sz, {})
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grand_pent_hit[sz][k] = grand_pent_hit[sz].get(k, 0) + v
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for sz, dist in pt.items():
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for k, v in dist.items():
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grand_pent_tot.setdefault(sz, {})
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grand_pent_tot[sz][k] = grand_pent_tot[sz].get(k, 0) + v
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elapsed = time.time() - start
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print(f"n={n}: {n_bad_n} bad colourings [{elapsed:.0f}s]")
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sys.stdout.flush()
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grand_bad += n_bad_n
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print()
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print("=" * 70)
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print(f"Total bad colourings: {grand_bad}")
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print("\nIs S-cycle a face boundary of reduced dual?")
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for sz in sorted(grand_size):
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tot = grand_size[sz]
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face_count = grand_face_b.get(sz, 0)
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pct = 100 * face_count / max(tot, 1)
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print(f" |S| = {sz}: {face_count} / {tot} ({pct:.1f}%) yes")
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print("\nDistribution of # G'-pentagons HIT by S, by |S|:")
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for sz in sorted(grand_pent_hit):
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print(f" |S| = {sz}:")
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for h, c in sorted(grand_pent_hit[sz].items()):
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print(f" {h} pentagons hit: {c}")
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print("\nDistribution of # G'-pentagons TOTAL, by |S|:")
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for sz in sorted(grand_pent_tot):
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print(f" |S| = {sz}:")
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for t, c in sorted(grand_pent_tot[sz].items()):
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print(f" {t} pentagons total: {c}")
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print("\nKey check: is # hit ≤ |S| always?")
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for sz in sorted(grand_pent_hit):
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max_hit = max(grand_pent_hit[sz].keys())
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leq = max_hit <= sz
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print(f" |S| = {sz}: max # hit = {max_hit}, "
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f"{'≤' if leq else '>'} |S| ({'✓' if leq else '✗ violated'})")
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if __name__ == '__main__':
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main()
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