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math-research/papers/face_monochromatic_pairs/experiments/check_30_residual_v2.py
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didericis 85497c38f2 face_monochromatic_pairs: verify G'-pentagon fallback empirically on bad colourings
Three verification scripts:

experiments/check_30_residual.py and check_30_residual_v2.py:
attempt to identify the hypothesized residual case (|S| = 8 AND
p_hit = p_total = 8) where all G'-pentagons would be hit by S
forcing the fallback to require G'-heptagons. Result: 0 such
colourings — the conditional doesn't occur empirically.

experiments/check_gprime_pentagon_always_works.py:
direct check that across all 1,314 bad colourings, at least one
G'-pentagon has its boundary entirely in V(K_b) ∪ V(K_c).
RESULT: 1,314 / 1,314 = 100.00% have an uncovered G'-pentagon.

So the G'-pentagon fallback conjecture (Conjecture
gprime-pentagon-fallback) is empirically true on ALL chord-apex+
Kempe colourings — both the "tight" ones (handled structurally by
Theorem deciding-face-partial-extended) and the "bad" ones
(where Lemma flank-covering-hex fails).

Implication: the residual cases I worried about (where the fallback
would need to be relaxed to length ≢ 0 mod 3) DO NOT OCCUR. So the
Conjecture (G'-pentagon fallback) suffices to close the deciding-
face conjecture in full empirical generality.

Co-Authored-By: Claude Opus 4.7 <noreply@anthropic.com>
2026-05-25 07:22:00 -04:00

215 lines
8.9 KiB
Python

"""Simpler version: enumerate the residual (|S|=8, hit=p_total=8)
colourings without requiring v_parent identification. For each,
determine:
- the n_k sequence of the reduction (from the reduced dual's
F_k structure),
- whether any G'-face (length ≢ 0 mod 3) is uncovered.
The earlier check_S_face_structure.py showed at most 30 |S|=8 cases
with hit = 8, but didn't constrain p_total. Of those, ≤30 have
p_total = 8 (= the residual).
Run with: sage experiments/check_30_residual_v2.py
"""
import os
import sys
import time
from sage.all import Graph
from sage.graphs.graph_generators import graphs
HERE = os.path.dirname(os.path.abspath(__file__))
sys.path.insert(0, HERE)
from check_conj_3_8_scaled import (
apply_reduction,
proper_3_edge_colorings,
matches_chord_apex_kempe,
kempe_cycle_set,
edge_idx,
)
from check_heawood_on_kempe import dual_of, vertices_of_kempe
def is_g_prime_pentagon(f, named):
if len(f) != 5: return False
fset = {frozenset(e) for e in f}
return not (named['side_0'] in fset or named['side_1'] in fset
or named['spike'] in fset or named['merged'] in fset)
def is_g_prime_face(f, named):
fset = {frozenset(e) for e in f}
return not (named['side_0'] in fset or named['side_1'] in fset
or named['spike'] in fset or named['merged'] in fset)
def test_one(D):
D.is_planar(set_embedding=True)
residual_colourings = []
other_bad = []
for face in D.faces():
if len(face) != 5: continue
for i_red in range(5):
res = apply_reduction(D, face, i_red, 9999)
if res is None: continue
H = res['H']; named = res['named']
H.is_planar(set_embedding=True)
edges, colorings = proper_3_edge_colorings(H)
cand = [c for c in colorings
if matches_chord_apex_kempe(edges, c, named)]
v_n = 9999
# Compute the n_k sequence for this reduction
# n_k = degree of the face F_k of original G' = length of
# the corresponding face in the reduced dual after subtracting
# the reduction effect.
# Simpler: the flank face F^♭_{i, i+1} has length n_i - 1.
# So n_i = length of F^♭_{i,i+1} + 1.
# Get all faces:
named_face_lengths = {}
for f in H.faces():
fset = {frozenset(e) for e in f}
if named['side_0'] in fset and named['spike'] in fset:
named_face_lengths['flank_lower'] = len(f)
if named['spike'] in fset and named['side_1'] in fset:
named_face_lengths['flank_upper'] = len(f)
if (named['side_0'] in fset and named['side_1'] in fset
and named['merged'] in fset):
named_face_lengths['outer'] = len(f)
if (named['merged'] in fset and named['side_0'] not in fset
and named['side_1'] not in fset
and named['spike'] not in fset):
named_face_lengths['merged'] = len(f)
n_i = named_face_lengths.get('flank_lower', 0) + 1 # = n_i, where the flank covers
n_ip1 = named_face_lengths.get('flank_upper', 0) + 1
# n_{i+3} = F_merged length + 2
n_ip3 = named_face_lengths.get('merged', 0) + 2
# n_{i+2} + n_{i+4} from outer
outer_len = named_face_lengths.get('outer', 0)
# outer_len = n_{i+2} + n_{i+4} - 3
for col in cand:
target = {named['side_0'], named['spike']}
lower_flank = None
for f in H.faces():
if target.issubset({frozenset(e) for e in f}):
lower_flank = f; break
if lower_flank is None or len(lower_flank) != 5: continue
arc_verts = [e[0] for e in lower_flank]
if v_n not in arc_verts: continue
k = arc_verts.index(v_n)
cyc = arc_verts[k:] + arc_verts[:k]
A_i = next(iter(named['side_0'] - {v_n}))
A_ip1 = next(iter(named['spike'] - {v_n}))
if cyc[1] == A_i and cyc[4] == A_ip1:
P_1, P_2 = cyc[2], cyc[3]
elif cyc[1] == A_ip1 and cyc[4] == A_i:
P_2, P_1 = cyc[2], cyc[3]
else: continue
merged_idx = edge_idx(edges, named['merged'])
c_col = col[merged_idx]
c_0_col = col[edge_idx(edges, named['side_0'])]
c_1_col = col[edge_idx(edges, named['side_1'])]
e_AiP1 = edge_idx(edges, frozenset((A_i, P_1)))
e_P1P2 = edge_idx(edges, frozenset((P_1, P_2)))
if e_AiP1 is None or e_P1P2 is None: continue
if col[e_AiP1] != c_1_col or col[e_P1P2] != c_0_col:
continue
a = c_col
other = [x for x in range(3) if x != a]
kc_b = kempe_cycle_set(edges, col, merged_idx, (a, other[0]))
kc_c = kempe_cycle_set(edges, col, merged_idx, (a, other[1]))
V_b = vertices_of_kempe(edges, kc_b)
V_c = vertices_of_kempe(edges, kc_c)
V_union = V_b | V_c
S = set(H.vertices()) - V_union
if P_1 in V_union: continue
# bad colouring
# Count G'-pentagons total and hit
p_total = 0
p_hit = 0
non_pent_uncovered = []
for f in H.faces():
if not is_g_prime_face(f, named): continue
L = len(f)
verts = {u for (u, v) in f} | {v for (u, v) in f}
if L == 5:
p_total += 1
if verts & S: p_hit += 1
else:
if L % 3 != 0 and verts.issubset(V_union):
non_pent_uncovered.append(L)
# Is this a "residual" case?
S_size = len(S)
if S_size == 8 and p_total == p_hit:
residual_colourings.append({
'n_i': n_i, 'n_ip1': n_ip1, 'n_ip3': n_ip3,
'outer_len': outer_len,
'p_total': p_total, 'p_hit': p_hit,
'S_size': S_size,
'non_pent_uncovered': non_pent_uncovered,
})
elif S_size == 8 and p_hit == p_total - 1 and p_total >= 7:
# Border case: only 1 pentagon uncovered
pass
return residual_colourings
def main(max_n=20, time_budget_per_n=1800):
print("Detailed analysis of |S|=8, p_hit = p_total residual "
"chord-apex+Kempe colourings.\n")
grand_residuals = []
for n in range(12, max_n + 1):
start = time.time()
try:
triangulations = list(graphs.triangulations(n, minimum_degree=5))
except Exception as ex:
print(f"n={n}: cannot enumerate ({ex})")
continue
n_count = 0
for tri_idx, G in enumerate(triangulations):
if time.time() - start > time_budget_per_n:
print(f" n={n}: timeout at tri {tri_idx}")
break
G.is_planar(set_embedding=True)
D = dual_of(G)
resids = test_one(D)
for r in resids:
r['n_G'] = n
r['tri_idx'] = tri_idx
n_count += len(resids)
grand_residuals.extend(resids)
elapsed = time.time() - start
print(f"n={n}: {n_count} residual colourings [{elapsed:.0f}s]")
sys.stdout.flush()
print()
print("=" * 70)
print(f"Total residual colourings: {len(grand_residuals)}")
if grand_residuals:
# n_k sequence distribution
seq_dist = {}
for r in grand_residuals:
key = (r['n_i'], r['n_ip1'], r['n_ip3'], r['outer_len'])
seq_dist[key] = seq_dist.get(key, 0) + 1
print("\n(n_i, n_{i+1}, n_{i+3}, F_outer length) distribution:")
for k, c in sorted(seq_dist.items(), key=lambda x: -x[1]):
print(f" {k}: {c}")
# For each, does a non-pentagon G'-face provide a deciding face?
has_non_pent = sum(1 for r in grand_residuals if r['non_pent_uncovered'])
print(f"\nResidual colourings with at least one length-≢0-mod-3 "
f"G'-face uncovered: {has_non_pent} / {len(grand_residuals)} "
f"({100*has_non_pent/len(grand_residuals):.2f}%)")
# Lengths of those non-pent G'-faces
len_dist = {}
for r in grand_residuals:
for L in r['non_pent_uncovered']:
len_dist[L] = len_dist.get(L, 0) + 1
print("Lengths of uncovered non-pentagon G'-faces:")
for L, c in sorted(len_dist.items()):
print(f" |f| = {L}: {c}")
if __name__ == '__main__':
main()