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math-research/papers/face_monochromatic_pairs/experiments/check_combinatorial_winding.py
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didericis fd4b89a39e face_monochromatic_pairs: try winding-number approach (option 4) — does not yield contradiction
Approach: at each vertex of a simple closed cycle C in a 3-regular
planar graph, define turn-sign(v) = +1 if the third edge (off-cycle)
is in C's bounded region (interior), -1 if exterior. Compute
Σ_v turn-sign(v).

Empirical check on standard graphs (K_4, Q_3, dodecahedron, 3-prism):
For a FACE boundary, Σ = -L_face (all third edges outside the face).
For a NON-face cycle, Σ can range from -L to +L.

Plan: under Lemma 5.2's alternation hypothesis (constancy on V(K_b)
forces third edges to alternate sides along K_b), the signs alternate
+,-,+,-,... yielding Σ = 0 for K_b of even length.

This shows K_b is NOT a face boundary (= it bounds a region containing
other vertices/edges), which is true but not a contradiction.
A simple closed planar curve can have Σ = 0; that just means equal
numbers of off-cycle edges are inside vs outside.

So the winding-number approach (option 4) does not yield a direct
contradiction under the chord-apex+Kempe + constancy hypothesis.

Co-Authored-By: Claude Opus 4.7 <noreply@anthropic.com>
2026-05-25 06:10:54 -04:00

167 lines
6.3 KiB
Python

"""Verify the combinatorial winding invariant for simple closed cycles
in a 3-regular planar graph:
Claim: For a simple closed cycle C in a 3-regular planar graph H
(with C ⊆ E(H), |C|/2 edges of C at each vertex of C), walked CCW
around its interior, define for each v ∈ V(C):
turn-sign(v) = +1 if the third edge (= the one of v's 3 edges NOT
on C) is on the OUTSIDE of C, locally at v.
(= the walker turns LEFT into the interior).
-1 if the third edge is on the INSIDE.
Hypothesis: Σ_v turn-sign(v) = ±6 (= ±(L_C / |V|_C-cycle-curvature)).
This is a combinatorial Gauss-Bonnet for cubic plane graphs:
internal/external turn parity around any face / cycle.
Sanity-check this on:
- Triangle (length 3) in K_4.
- Quadrilateral (length 4) in Q_3.
- Pentagon (length 5) in dodecahedron.
- Hexagon (length 6) in some triangulation dual.
Also on Kempe cycles in chord-apex+Kempe colourings of reduced duals.
If the invariant holds (always ±6), then combining with Lemma 5.2's
alternation (= turn signs alternate +,-,+,- on any K_b under constancy),
we'd have #(+) = #(-) = L_b / 2, so #(+) - #(-) = 0 ≠ ±6, giving a
direct contradiction.
Run with: sage experiments/check_combinatorial_winding.py
"""
import os
import sys
from sage.all import Graph
from sage.graphs.graph_generators import graphs
def cycle_winding(G, cycle_vertices):
"""Compute Σ_v turn-sign(v) for a simple closed cycle in 3-reg planar G.
cycle_vertices: list of vertices in walking order around the cycle.
Walking direction: CCW (= traversal such that interior is on the LEFT).
For each v in the cycle, the 3 edges at v are split as: 2 cycle
edges (to v's neighbours in the cycle) and 1 third edge (off-cycle).
The third edge is at some position in v's CW rotation system.
turn-sign(v) = +1 if the third edge is OUTSIDE the cycle (= on the
right of the CCW walk locally), -1 if INSIDE.
"""
G.is_planar(set_embedding=True)
emb = G.get_embedding()
L = len(cycle_vertices)
total = 0
for k in range(L):
v = cycle_vertices[k]
prev = cycle_vertices[(k - 1) % L]
nxt = cycle_vertices[(k + 1) % L]
# CW rotation at v: emb[v] is the list of neighbours in CW
# order.
nbrs = emb[v]
# We need positions of prev, nxt, and third.
if prev not in nbrs or nxt not in nbrs:
return None
# The third edge endpoint:
third = [u for u in nbrs if u != prev and u != nxt]
if len(third) != 1:
return None
third = third[0]
# CW order of (prev, nxt, third) in emb[v]:
idx_prev = nbrs.index(prev)
idx_nxt = nbrs.index(nxt)
idx_third = nbrs.index(third)
# In CW order, what's the cyclic arrangement?
# Walking CCW around the cycle means walker is on edge (prev, v),
# at v, and exits via (v, nxt). The interior of the cycle is
# on the LEFT of the walker.
# The third edge is at idx_third in CW rotation.
# If we go CW from idx_prev to idx_nxt:
# - if idx_third is in this CW interval, third is on one side;
# - else on the other side.
# For 3-regular vertex with CW order (positions 0, 1, 2 cyclically),
# idx_prev, idx_nxt, idx_third are some permutation of {0, 1, 2}.
# Define: third is on the RIGHT of walker (= going CW from prev
# to nxt without passing through third) ⟺ third is NOT between
# prev and nxt in CW direction.
# The CW order at v: nbrs[0], nbrs[1], nbrs[2].
# CW direction at v: 0 → 1 → 2 → 0.
# CW from prev to nxt: starting at idx_prev, going CW (= +1 mod 3),
# we reach idx_nxt after some steps.
# If we pass through idx_third in 1 step: third is between prev
# and nxt in CW direction (i.e., on one specific side).
# If we don't pass through idx_third (= go directly from prev to
# nxt in 1 CW step): third is on the OTHER side.
# 1 CW step from idx_prev: (idx_prev + 1) % 3.
if (idx_prev + 1) % 3 == idx_nxt:
# CW step from prev to nxt is direct (1 step).
# Third is at the "other" position, NOT between in CW.
# This means third is on the "left" of walker going CCW
# along the cycle (= interior side).
# turn-sign = -1 (third inside).
sign = -1
elif (idx_prev + 2) % 3 == idx_nxt:
# CW step from prev to nxt is 2 steps (passing through
# idx_third).
# Third is BETWEEN prev and nxt in CW direction.
# turn-sign = +1 (third outside, walker turns left into
# interior).
sign = +1
else:
return None
total += sign
return total
def face_to_cycle(face):
"""Convert face (= list of edges) to ordered vertex cycle."""
if not face:
return None
verts = [face[0][0]]
for e in face:
verts.append(e[1])
return verts[:-1] # last vertex = first vertex
def main():
tests = []
# K_4 = tetrahedron
K4 = graphs.CompleteGraph(4)
K4.is_planar(set_embedding=True)
tests.append(('K_4', K4))
# Q_3 = cube
Q3 = graphs.CubeGraph(3)
Q3.is_planar(set_embedding=True)
tests.append(('Q_3', Q3))
# Dodecahedron
Dod = graphs.DodecahedralGraph()
Dod.is_planar(set_embedding=True)
tests.append(('Dodecahedron', Dod))
# Triangular prism
Tprism = graphs.CompleteBipartiteGraph(2, 3) # not 3-regular
# Use Q3 plus more
tests.append(('Triangular prism (3-prism)', graphs.GeneralizedPetersenGraph(3, 1)))
for name, G in tests:
if not all(G.degree(v) == 3 for v in G.vertex_iterator()):
print(f"\n{name}: NOT 3-regular (degree set = "
f"{sorted(set(G.degree()))}); skipping")
continue
if not G.is_planar(set_embedding=True):
print(f"\n{name}: NOT planar; skipping")
continue
print(f"\n{name}: |V|={G.order()}, |E|={G.size()}, faces:")
faces = G.faces()
for f in faces:
cyc = face_to_cycle(f)
if cyc is None:
print(f" bad face")
continue
w = cycle_winding(G, cyc)
print(f" face length {len(cyc)}, cycle={cyc}, winding={w}")
if __name__ == '__main__':
main()