406 lines
17 KiB
TeX
406 lines
17 KiB
TeX
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\documentclass{amsart}
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\begin{document}
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\title{Medial Tire Decompositions of Plane Triangulations}
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% author one information
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\author{Eric Bauerfeld}
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\address{}
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\curraddr{}
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\email{}
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\thanks{}
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\subjclass[2010]{Primary }
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\keywords{plane graph, triangulation, medial graph, tire graph, Tait coloring, Four Colour Theorem}
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\date{}
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\dedicatory{}
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\begin{abstract}
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We use the nested tire decomposition of a plane triangulation to induce
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a decomposition of its full medial graph into medial tire subgraphs.
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For a plane triangulation $G$, the medial graph $M(G)$ is naturally
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isomorphic to the medial graph of the planar dual $G^*$, and proper
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$3$-vertex-colourings of $M(G)$ are equivalent to proper
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$3$-edge-colourings of the cubic dual. Thus Tait's reformulation of
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the Four Colour Theorem may be studied through proper vertex
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$3$-colourings of medial subgraphs. We define medial tire pieces,
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their boundary-state restriction relations, and a chain-pigeonhole
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conjecture for compatible medial boundary states across the tire tree.
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\end{abstract}
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\maketitle
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\section{Introduction}
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A classical theorem of Tait recasts the Four Colour Theorem in dual,
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edge-colouring terms: a plane triangulation $G$ is properly
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$4$-vertex-colourable if and only if its dual cubic graph $G^*$ is
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properly $3$-edge-colourable. The present paper records a medial
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version of this viewpoint. The vertices of the medial graph $M(G)$
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correspond to edges of $G$, and adjacency in $M(G)$ records
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consecutiveness of edges around vertices and faces of $G$. Since
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planar duality interchanges vertices and faces while preserving the
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edge set, $M(G)$ is naturally isomorphic to $M(G^*)$.
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Consequently a proper vertex $3$-colouring of $M(G)$ is the same
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object as a proper edge $3$-colouring of $G^*$. This suggests another
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route toward the Four Colour Theorem: rather than colouring the dual
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cubic graph directly, decompose the full medial graph into local
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annular pieces and try to prove that their proper vertex
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$3$-colouring boundary restrictions always compose.
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The structural input is the nested tire decomposition of
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\cite{bauerfeld-nested-tire-decompositions}. A level source in a plane
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triangulation determines a rooted tree of tire treads. Each tread is
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an annular triangulated region with an outer boundary, an inner
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outerplanar graph, and annular triangular faces. We show that this
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decomposition induces a decomposition of $M(G)$ into medial tire
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subgraphs. The boundary data of a medial tire are proper
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$3$-colourings of the medial vertices corresponding to boundary edges
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in the associated dual tire graph.
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\section{Background}
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Throughout, $G$ is a simple plane maximal planar graph with fixed
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embedding, and $G^*$ denotes its full planar dual. We use the level
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source, dual depth, tire graph, tire tread, and tire-tree terminology
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of~\cite{bauerfeld-nested-tire-decompositions}. In particular, a level
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source $S$ determines a rooted tire tree $\mathcal{T}(G,S)$ whose
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vertices are tire treads and whose parent-child relation records
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nested containment across level-cycle interfaces.
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\begin{definition}[Medial graph]
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\label{def:medial-graph}
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Let $H$ be a plane graph. The \emph{medial graph} $M(H)$ has one
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vertex $m_e$ for each edge $e \in E(H)$. Two medial vertices
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$m_e,m_f$ are adjacent whenever $e$ and $f$ are consecutive in the
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cyclic order of edges around a vertex of $H$ or around a face of $H$.
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The embedding is the standard one obtained by placing $m_e$ at the
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midpoint of $e$ and drawing medial edges through the vertex- and
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face-corners of $H$.
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\end{definition}
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\begin{remark}
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If $H$ has bridges or vertices of degree $1$, the usual medial
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construction may create parallel edges or loops depending on the
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chosen convention. In this paper the main application is to plane
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triangulations and their cubic planar duals, where the medial graph is
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a loopless $4$-regular plane graph.
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\end{remark}
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\begin{proposition}[Medial dual invariance]
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\label{prop:medial-dual-invariance}
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Let $H$ be a connected plane graph and let $H^*$ be its planar dual.
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Then there is a natural plane-graph isomorphism
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\[
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M(H) \cong M(H^*).
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\]
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\end{proposition}
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\begin{proof}
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Each edge $e \in E(H)$ corresponds to a unique dual edge $e^* \in
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E(H^*)$, giving a bijection $m_e \mapsto m_{e^*}$ between the vertices
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of $M(H)$ and $M(H^*)$. In $M(H)$ two vertices $m_e,m_f$ are adjacent
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exactly when $e$ and $f$ are consecutive around either a vertex or a
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face of $H$. Under duality, vertices and faces are interchanged, and
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the cyclic order of the corresponding dual edges around the dual face
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or dual vertex is the same up to reversal. Thus the same pairs are
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medial-adjacent in $M(H^*)$, and the midpoint construction identifies
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the two embedded medial graphs.
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\end{proof}
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\begin{corollary}[Tait colourings as medial vertex colourings]
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\label{cor:tait-medial}
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Let $G$ be a simple plane triangulation. Proper vertex
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$3$-colourings of $M(G)$ are in natural bijection with proper
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$3$-edge-colourings of the cubic planar dual $G^*$.
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\end{corollary}
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\begin{proof}
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By Proposition~\ref{prop:medial-dual-invariance}, $M(G) \cong
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M(G^*)$. Vertices of $M(G^*)$ correspond to edges of $G^*$, and two
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such vertices are adjacent exactly when the corresponding dual edges
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are incident and consecutive around a vertex or face of $G^*$. Since
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$G^*$ is cubic, proper vertex $3$-colouring of $M(G^*)$ is therefore
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equivalent to assigning three colours to the edges of $G^*$ so that the
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three edges incident to each dual vertex receive pairwise distinct
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colours.
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\end{proof}
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\section{Medial tire pieces}
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\begin{definition}[Full medial tire graph]
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\label{def:full-medial-tire}
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Let $T$ be a tire tread in the tire tree $\mathcal{T}(G,S)$ supplied
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by~\cite{bauerfeld-nested-tire-decompositions}. The \emph{full medial
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tire graph} of $T$, denoted $\mathsf{M}(T)$, is the subgraph of
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$M(G)$ induced by the medial vertices $m_e$ with $e$ an edge of $G$
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incident to at least one triangular face in the tread $T$. The medial
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vertices corresponding to annular edges of $T$ are called
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\emph{annular medial vertices}.
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\end{definition}
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\begin{remark}
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In the ambient-triangulation setting, the full medial tire graph
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$\mathsf{M}(T)$ coincides with the omitted-edge medial tire graph
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studied in~\cite{bauerfeld-nested-tire-decompositions}. Indeed, the
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medial edges of $\mathsf{M}(T)$ are contributed by corners of annular
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triangular tread faces. Such a face contains at most one outer-boundary
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edge and at most one inner-boundary edge, so it does not contribute a
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medial edge between two outer-boundary edges or between two
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inner-boundary edges. Similarly, chords of the inner outerplanar graph
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lie outside the annular tread and are not incident to annular tread
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faces. Thus the deletion rule used for the earlier reduced medial tire
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graph removes no edges from the ambient object $\mathsf{M}(T)$.
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The distinction only appears in the standalone drawing convention where
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the outer and inner boundary walks are added as artificial faces before
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forming a medial graph. Those artificial faces create same-boundary
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medial edges, and the reduced construction deletes them.
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\end{remark}
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\begin{theorem}[Annular medial colour bound]
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\label{thm:annular-medial-colour-bound}
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Let $T = (B_{\mathrm{out}}, O, E_{\mathrm{ann}})$ be a tire tread with
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non-degenerate boundaries and simple inner boundary $B_{\mathrm{in}}$.
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Let $A(T)$ be the subgraph of $\mathsf{M}(T)$ induced by the annular
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medial vertices. For a graph $H$, write $\operatorname{Col}_3(H)$ for
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the set of proper $3$-vertex-colourings of $H$. Then $A(T)$ is a cycle
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and
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\[
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|\operatorname{Col}_3(\mathsf{M}(T))|
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\;\leq\; |\operatorname{Col}_3(A(T))|.
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\]
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\end{theorem}
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\begin{proof}
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Since the tread is a triangulated annulus with no vertices in its
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interior, each annular face has exactly one boundary edge, lying either
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on $B_{\mathrm{out}}$ or on $B_{\mathrm{in}}$, and exactly two annular
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edges. As the annular faces are traversed cyclically around the tread,
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consecutive faces share one annular edge. Equivalently, the annular
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edges occur in a cyclic order in which each annular face contains two
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consecutive annular edges. Hence the subgraph of $\mathsf{M}(T)$
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induced by the annular medial vertices is a cycle.
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Consider the restriction map from proper $3$-colourings of
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$\mathsf{M}(T)$ to colourings of this annular medial cycle $A(T)$. We
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claim that this map is injective. Let $x$ be a non-annular medial
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vertex. Then $x$ corresponds to an edge of $B_{\mathrm{out}}$ or
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$B_{\mathrm{in}}$: chords of $O$ are not incident to annular tread
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faces, and hence do not contribute vertices of $\mathsf{M}(T)$. This
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boundary edge is incident to a unique annular face of the tread, and
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the other two edges of that face are annular edges. Therefore $x$ is
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adjacent in $\mathsf{M}(T)$ to the two annular medial vertices
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corresponding to those two annular edges.
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Those two annular medial vertices are adjacent to each other, because
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their annular edges are consecutive on the same triangular annular
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face. In any proper $3$-colouring they therefore receive two distinct
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colours, and $x$ is forced to receive the remaining third colour. Thus
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every non-annular medial vertex has its colour uniquely determined by
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the colouring of $A(T)$. Two colourings of $\mathsf{M}(T)$ with the
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same restriction to $A(T)$ are identical, so the restriction map is
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injective. The stated inequality follows.
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\end{proof}
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\begin{definition}[Boundary medial vertices]
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\label{def:boundary-medial-vertices}
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Let $T$ be a tire tread and let $\Gamma_T$ be the corresponding dual
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tire subgraph in $G^*$. A vertex $m_e \in V(\mathsf{M}(T))$ is an
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\emph{outer boundary medial vertex} if the corresponding dual edge
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$e^* \in E(G^*)$ lies on the outer boundary of $\Gamma_T$. It is an
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\emph{inner boundary medial vertex} if $e^*$ lies on the inner boundary
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of $\Gamma_T$. We write
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\[
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\partial_{\mathrm{out}}\mathsf{M}(T)
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\quad\text{and}\quad
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\partial_{\mathrm{in}}\mathsf{M}(T)
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\]
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for the two boundary sets.
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\end{definition}
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\begin{definition}[Medial tire restriction relation]
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\label{def:medial-restriction-relation}
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Let $\mathrm{Col}_3(X)$ denote the set of proper vertex
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$3$-colourings of the induced subgraph on a vertex set $X$. The
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\emph{medial tire restriction relation} of $T$ is
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\[
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R_T \subseteq
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\mathrm{Col}_3(\partial_{\mathrm{out}}\mathsf{M}(T))
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\times
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\mathrm{Col}_3(\partial_{\mathrm{in}}\mathsf{M}(T)),
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\]
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where $(\alpha,\beta) \in R_T$ exactly when $\alpha \cup \beta$
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extends to a proper vertex $3$-colouring of $\mathsf{M}(T)$.
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\end{definition}
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\begin{remark}
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The definition deliberately records boundary colourings on medial
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vertices corresponding to boundary edges in the dual tire graph. Under
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Corollary~\ref{cor:tait-medial}, these are precisely edge-colouring
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states on the boundary edges through which a dual tire piece meets its
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parent and children.
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\end{remark}
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\section{Decomposition}
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\begin{corollary}[Medial tire decomposition]
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\label{cor:medial-tire-decomposition}
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Let $G$ be a plane triangulation with level source $S$. The tire-tree
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decomposition $\mathcal{T}(G,S)$ of
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\cite{bauerfeld-nested-tire-decompositions} induces a rooted
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decomposition of the full medial graph $M(G)$ into full medial tire
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graphs $\{\mathsf{M}(T): T \in V(\mathcal{T}(G,S))\}$, glued along
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their boundary medial vertex sets.
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\end{corollary}
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\begin{proof}
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By the tire-tread partition theorem of
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\cite{bauerfeld-nested-tire-decompositions}, the bounded triangular
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faces of $G$ are partitioned into nested tire treads, with intersections
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between parent and child treads occurring only along their level-cycle
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interface data. Every edge of $G$ that is incident to a bounded face
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therefore belongs to the closure of at least one tire tread, and an
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edge lying in two closures lies on the interface between adjacent
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treads in the tire tree. Passing to $M(G)$ sends edges of $G$ to
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medial vertices. Thus each tread determines the induced subgraph
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$\mathsf{M}(T)$ on its incident edge set, and overlaps between two such
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subgraphs are exactly the medial vertices corresponding to interface
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edges, namely the appropriate boundary medial vertex sets.
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\end{proof}
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\begin{definition}[Compatible family of medial tire colourings]
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\label{def:compatible-family}
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A \emph{compatible family of medial tire colourings} on
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$\mathcal{T}(G,S)$ is a choice, for each tread $T$, of a proper
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vertex $3$-colouring $\varphi_T$ of $\mathsf{M}(T)$ such that whenever
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$T'$ is a child tread of $T$, the two colourings agree on
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$
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V(\mathsf{M}(T)) \cap V(\mathsf{M}(T')).
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$
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\end{definition}
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\begin{proposition}[Gluing criterion]
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\label{prop:gluing-criterion}
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The full medial graph $M(G)$ has a proper vertex $3$-colouring if and
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only if the tire tree $\mathcal{T}(G,S)$ admits a compatible family of
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medial tire colourings.
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\end{proposition}
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\begin{proof}
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A proper vertex $3$-colouring of $M(G)$ restricts to a proper vertex
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$3$-colouring of every induced subgraph $\mathsf{M}(T)$, and these
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restrictions agree on overlaps.
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Conversely, suppose a compatible family is given. Define a colour on
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each vertex $m_e$ of $M(G)$ by choosing any tread $T$ with
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$m_e \in V(\mathsf{M}(T))$ and setting
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$\varphi(m_e)=\varphi_T(m_e)$. Compatibility makes this independent of
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the choice of $T$. Every medial edge of $M(G)$ is drawn in a corner of
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some bounded triangular face of $G$ or along the outer boundary
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interface. The relevant incident primal edges lie together in the
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closure of a single tire tread or in a shared boundary interface, where
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properness is already enforced by one of the local colourings. Hence
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$\varphi$ is a proper vertex $3$-colouring of $M(G)$.
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\end{proof}
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\section{A medial pigeonhole programme}
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The restriction relation $R_T$ records exactly the local information
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needed to pass a medial $3$-colouring through a tire. In a nested
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chain
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\[
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T_0 \supset T_1 \supset \cdots \supset T_k,
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\]
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the outer boundary state of $T_{i+1}$ must match an inner boundary
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state allowed by $R_{T_i}$. Thus a proof of the Four Colour Theorem in
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this framework would follow from a structural reason that these
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restriction sets cannot remain mutually disjoint along every branch of
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the tire tree.
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\begin{definition}[Medial boundary state]
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\label{def:medial-boundary-state}
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A \emph{medial boundary state} on a boundary set
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$\partial\mathsf{M}(T)$ is a proper vertex $3$-colouring of the
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subgraph induced by that boundary set, considered up to permutation of
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the three colours and the dihedral symmetries of the boundary walk
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when that boundary is a cycle.
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\end{definition}
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\begin{conjecture}[Medial chain-pigeonhole principle]
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\label{conj:medial-chain-pigeonhole}
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There is a function $N(k)$ such that the following holds. Let
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$T_0 \supset T_1 \supset \cdots \supset T_{N(k)}$ be a nested chain of
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tire treads whose relevant boundary medial walks have length at most
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$k$. Then two adjacent restriction relations in the chain have
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compatible medial boundary states after colour permutation and boundary
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symmetry. Equivalently, the chain contains a local gluing step that
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cannot be obstructed by disjoint proper vertex $3$-colouring
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restrictions.
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\end{conjecture}
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\begin{conjecture}[Medial tire route to the Four Colour Theorem]
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\label{conj:medial-route-fct}
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For every plane triangulation $G$ and every level source $S$, the
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restriction relations $\{R_T : T \in V(\mathcal{T}(G,S))\}$ admit a
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compatible selection of boundary states across the tire tree. Hence
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$M(G)$ is properly vertex $3$-colourable, $G^*$ is properly
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$3$-edge-colourable, and $G$ is properly $4$-vertex-colourable.
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\end{conjecture}
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\begin{remark}
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Conjecture~\ref{conj:medial-route-fct} is equivalent in strength to
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the Four Colour Theorem when combined with Tait's correspondence. The
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point of the formulation is not to weaken the target theorem, but to
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move the obstruction into finite boundary-state restrictions carried by
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annular medial tire pieces.
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\end{remark}
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\begin{thebibliography}{9}
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\bibitem{bauerfeld-nested-tire-decompositions}
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E.~Bauerfeld,
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\emph{Nested Tire Decompositions of Plane Triangulations},
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manuscript (math-research repository), 2026.
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\bibitem{tait-original}
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P.~G. Tait,
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\emph{Remarks on the colourings of maps},
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Proceedings of the Royal Society of Edinburgh \textbf{10} (1880),
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729--729.
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\end{thebibliography}
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\end{document}
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