coloring_nested_tire_graphs: note the antipodal-chord rainbow conjecture; cross-link from step-2
Promotes the orbit_decomposition finding (rainbow orbit appears in 3
different (T_1, T_2) pairs, all with T_1 = (6, (0,3), SP)) into an
explicit conjecture:
Conjecture (Obs:antipodal-rainbow-conjecture):
For T = (m, (0, m/2), SP) (an antipodal-chord SP tire with m even),
π_D(C(T)) always contains the combined orbit of
(a, b, c, b, c, ..., b, c, a) under S_3 × C_m, with the a-positions
at the chord endpoints and b/c alternating elsewhere.
If true, this gives a uniform structural property of antipodal-chord
SP tires: chain pigeonhole on |γ| = m shared cycles reduces to
"π_U of the other tire meets this fixed orbit." Tested at m = 6 in
3 pairs; the m = 4 direct test (24-element conjectured orbit ⊂
36-element support) is mechanical.
Also adds a forward-pointer paragraph at the end of Obs:rainbow in
tire_fiber_step2.tex referencing orbit_decomposition.tex.
orbit_decomposition.tex: 3 pages -> 3 pages (added Conjecture section
and a "why antipodal?" paragraph).
Co-Authored-By: Claude Opus 4.7 <noreply@anthropic.com>
This commit is contained in:
@@ -3,4 +3,7 @@
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\newlabel{obs:orbit-sizes}{{}{1}}
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\newlabel{obs:rainbow-source}{{}{2}}
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\newlabel{obs:universal-orbits}{{}{2}}
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\newlabel{obs:antipodal-rainbow-conjecture}{{}{3}}
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\@writefile{toc}{\contentsline {paragraph}{Direct test.}{3}{}\protected@file@percent }
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\@writefile{toc}{\contentsline {paragraph}{Why antipodal?}{3}{}\protected@file@percent }
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topology, not a coincidence of one specific configuration.
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\end{itemize}
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\section*{Conjecture suggested by the data}
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\begin{obs}[Antipodal-chord rainbow conjecture]
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\label{obs:antipodal-rainbow-conjecture}
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Let $T = (m, (0, m/2), \mathrm{SP})$ be a Steiner-poor tire whose
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inner outerplanar graph $O$ is a cycle of length $m$ together with a
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single antipodal chord (so $m$ is even). Conjecture: the projection
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support $\pi_D(\mathcal{C}(T))$ on the $|\gamma| = m$ inner-side
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spokes always contains the combined orbit
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\[
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\mathrm{Orbit}\bigl(\,(a, b, c, b, c, \dots, b, c, a)\,\bigr)
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\]
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under $S_3 \times C_m$ (color permutation $\times$ cyclic rotation),
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where the pattern has length $m$ and the $a$-positions are exactly
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the two chord endpoints, with $b$ and $c$ alternating elsewhere.
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At $m = 6$ this is the rainbow orbit of size $36$ that
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Obs.~\ref{obs:rainbow-source} witnessed.
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\end{obs}
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If true, this is a uniform structural property of the antipodal-chord
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SP tire, independent of the outer boundary length. The chain
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pigeonhole step at $|\gamma| = m$ on such a tire reduces to
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``$\pi_U$ of the other tire intersects this fixed orbit,'' a much
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smaller compatibility claim.
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\paragraph{Direct test.} At $m = 4$ ($\theta(1, 2, 2) = K_4 - e$) the
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antipodal-chord SP tire's $\pi_D$ support has size $36$ at $|\gamma| =
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4$ (\texttt{tire\_fiber\_chords.tex}, row ``(4,4) chord $(0,2)$''),
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and the conjectured orbit $(a, b, c, b) \cdot S_3 \times C_4$ has size
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$24$. Confirming the conjecture at $m = 4$ amounts to checking that
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this $24$-element subset lies inside the $36$-element support; this
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is mechanical.
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\paragraph{Why antipodal?} In the planar dual picture, the antipodal
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chord of $O$ corresponds to the dual edge of a single
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``maximally-separating'' chord in the tire's inner outerplanar graph:
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it splits $\pi_1$ of the annulus most symmetrically. Any reasonable
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proof of the conjecture would have to exploit this symmetry --- e.g.\
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via reflection invariance on the chord axis.
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\section*{Caveats}
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\begin{enumerate}
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@@ -3,4 +3,4 @@
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\newlabel{obs:containment}{{}{2}}
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\newlabel{obs:rainbow}{{}{2}}
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\newlabel{obs:reflection}{{}{3}}
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@@ -140,6 +140,22 @@ antipodal positions are aligned with the antipodal chord
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$(v_0, v_3)$, and the pattern factors through the $S_3$ orbit. The
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fact that this very small intersection still contains an entire
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$S_3$-orbit is suggestive of structural rather than accidental overlap.
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\medskip
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\noindent\emph{Follow-up.} An $S_3$-orbit decomposition of all $23$
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intersections (\texttt{orbit\_decomposition.tex}) shows: every
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intersection is closed under the diagonal $S_3$ action; every non-
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trivial orbit has size $6$; and the rainbow combined orbit
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$(a, b, c, b, c, a) \cdot (S_3 \times C_6)$ appears in three different
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$(T_1, T_2)$ pairs, all sharing $T_1 = (6, (0, 3), \mathrm{SP})$
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(the antipodal-chord SP tire) but with $T_2$ ranging over chordless
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$\mathrm{SR}$, chordless $\mathrm{SP}$, and two-chord $\mathrm{SP}$
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configurations. This promotes the observation from
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``one $(T_1, T_2)$'s small intersection happens to be $S_3$-symmetric''
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to ``the antipodal-chord SP tire forces this orbit into every
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$\pi_D$-support, regardless of the other side.'' The candidate
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conjecture is recorded in \texttt{orbit\_decomposition.tex},
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Obs.\ \ref{obs:rainbow} (\emph{loc.\ cit.}).
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\end{obs}
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\begin{obs}[Reflection sensitivity]
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