Add bridge switch / bridge-derived level graph; set up exhaustive test
- Define bridge switch (E/O switch whose new same-parity edge is a bridge in its parity subgraph) and bridge-derived level graph in the paper. Note that bridge switches preserve bipartite parity subgraphs, so every bridge-derived level graph is automatically valid. - Discover the E/O-switch relation is directed (irreversible when a switch produces a cross-parity edge); T*_9 reaches an ELG forward but no ELG reaches it, explaining why it is not derived. This rules out a simple switch-invariant characterization. - Bridge orbits are far smaller than full E/O orbits (~10^4 vs ~10^8 for some labellings), making exhaustive search feasible. Each of the 4 open duals has ~150 valid parity partitions; exhaustive bridge-orbit search per partition can decide bridge-derivability conclusively. Co-Authored-By: Claude Opus 4.7 <noreply@anthropic.com>
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@@ -250,6 +250,37 @@ A derived level graph $G'$ is \emph{valid} if both $E_{G,S}(G')$ and
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$O_{G,S}(G')$ contain only even cycles.
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\end{definition}
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\begin{definition}[Bridge switch]
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\label{def:bridge-switch}
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Let $G'$ be a triangulation reached from an Even Level Graph $G$, with
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parity classes inherited from $G$ as in
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Definition~\ref{def:derived-level-graph}. An edge switch on an edge
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$e \in E \cup O$ of $G'$, replacing $uvw, uvx$ by the edge $wx$, is a
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\emph{bridge switch} if either
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\begin{itemize}
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\item the new edge $wx$ is a cross-parity edge (one endpoint even, the
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other odd), so $wx$ enters neither parity subgraph; or
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\item $wx$ is a same-parity edge and is a \emph{bridge} in the parity
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subgraph it joins -- that is, $w$ and $x$ lie in different connected
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components of that parity subgraph, so adding $wx$ creates no new cycle.
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\end{itemize}
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\end{definition}
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\begin{definition}[Bridge-derived level graph]
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\label{def:bridge-derived-level-graph}
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A \emph{bridge-derived level graph} of an Even Level Graph $G$ is a
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triangulation obtained from $G$ by a sequence of bridge switches
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(Definition~\ref{def:bridge-switch}).
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\end{definition}
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Because a bridge switch never closes a cycle in a parity subgraph, it
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never introduces an odd cycle there. As an Even Level Graph has
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bipartite parity subgraphs (every level cycle is even), every
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bridge-derived level graph has bipartite parity subgraphs as well, and
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so is automatically a valid derived level graph. Equivalently, the
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first Betti number of each parity subgraph is non-increasing along any
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sequence of bridge switches.
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\begin{definition}[Intertwining tree]
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\label{def:intertwining-tree}
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A maximal planar graph $G$ is an \emph{intertwining tree} if its
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