Add related-work section, refute floor-containment conjecture

Introduction now positions the tire-tree decomposition against
Birkhoff, Tutte, Heesch, Robertson-Sanders-Seymour-Thomas, and
Dvorak-Lidicky's coloring count cones (closest modern parallel).

Floor-containment conjecture refuted at n=4 and n=6: explicit
counterexample colorings (1,2,1,2), (1,3,2,1,3,2), (2,3,2,3,2,3)
absent from non-floor supports.  Skip-m=3 sweep through m=8 partial
still consistent with floor-stability-in-m.

Co-Authored-By: Claude Opus 4.7 <noreply@anthropic.com>
This commit is contained in:
2026-06-03 00:09:58 -04:00
parent 57f5c2839a
commit 35d226f8f8
7 changed files with 288 additions and 154 deletions
@@ -327,6 +327,38 @@ def enumerate_level_cycle_supports(
return supports, stats
def check_floor_containment(
supports: dict[frozenset[tuple[int, ...]], list[dict]],
) -> None:
"""Test whether the smallest-size support is a subset of every other support.
The supports are fully normalized (orbits under S_4 x D_n), so set
inclusion here is the right test for the "floor support is contained in
every admissible support" conjecture.
"""
if len(supports) < 2:
print(" containment: <2 supports, trivially contained")
return
keys = list(supports.keys())
min_size = min(len(k) for k in keys)
floors = [k for k in keys if len(k) == min_size]
print(f" containment check: floor support (size {min_size}) vs {len(keys) - 1} others")
for floor in floors:
bad: list[tuple[int, tuple[int, ...]]] = []
for other in keys:
if other is floor:
continue
if not floor.issubset(other):
missing = next(iter(floor - other))
bad.append((len(other), missing))
if not bad:
print(f" floor IS a subset of all {len(keys) - 1} other supports")
else:
print(f" floor is NOT a subset of {len(bad)} of {len(keys) - 1} other supports")
for size, missing in bad[:5]:
print(f" missing example: floor coloring {missing} absent from support of size {size}")
def summarize(
n: int,
supports: dict[frozenset[tuple[int, ...]], list[dict]],
@@ -357,6 +389,7 @@ def summarize(
print(f" most restrictive support : {min_size}/{all_colorings} ({len(min_supports)} support types)")
print(f" least restrictive support : {max_size}/{all_colorings}")
print(f" overlap among max-restrict : min {min(pair_overlaps)}, max {max(pair_overlaps)}")
check_floor_containment(supports)
print(" examples:")
printed = 0
@@ -239,3 +239,73 @@ opens the door to closed-form support computation for the worst case.
The obstruction to a quick proof is exotic `m ≥ 4` configurations not
reachable by subdivision from an `m = 3` floor witness — none has
appeared empirically, but their non-existence is not yet ruled out.
#### Skip-`m=3` sweep (partial)
To probe the conjecture more directly we ran a "skip-`m=3`" sweep
explicitly excluding `m = 3` from the search:
```bash
python3 -u papers/coloring_nested_tire_graphs/experiments/level_cycle_support.py \
--n-min 6 --n-max 6 --outer-min 4 --outer-max 10 --inner-min 7 --inner-max 9 \
--progress
```
The sweep ran for `11h 49m` and was terminated partway through `m = 8,
k = 9` at chord-set #6 of the 2-chord block (raw=6.45M canonical=223k).
Throughout the run --- across `m ∈ [4, 7]` exhaustively and `m = 8`
partially --- the distinct-support count stayed locked at **`13`**
(vs `19` for the full `m ∈ [3, 7]` run). The six missing support
types are precisely the ones with `m = 3`-only witnesses, including
the unique `252/732` floor.
Conclusion of the partial run: no support of size `≤ 252` appeared
under `m ≥ 4` in any configuration searched, and the support count
saturated early, suggesting the support landscape for `m ≥ 4` is
strictly looser than for `m = 3` even as `m` grows. The conjecture is
not falsified by any data we have; pushing `m` to `9` or `10` is
left as future work (path-count growth makes it expensive: `m = 10,
k = 9` alone has `C(19, 10) ≈ 92{,}000` paths per chord set).
### Floor-containment conjecture — refuted
Floor-stability bounds the *size* of the worst-case support but not
its content. For the tire-tree compatibility argument, what would
have closed the loop is a containment statement:
> **(Conjecture, refuted)** For every `n`, the unique floor support
> `F_n` is a *subset* of every admissible level-cycle support. Every
> level-cycle coloring that the `m = 3` floor witness allows is also
> allowed by every other tire.
The `check_floor_containment` helper in `level_cycle_support.py`
tests this directly on the computed supports. The conjecture **fails
at `n = 4` and `n = 6`**:
```text
n=4: floor (size 60) is NOT a subset of 1 of 2 other supports
missing: floor coloring (1, 2, 1, 2) absent from support of size 72
n=6: floor (size 252) is NOT a subset of 11 of 16 other supports
missing: floor coloring (1, 3, 2, 1, 3, 2) absent from support of size 708
missing: floor coloring (2, 3, 2, 1, 3, 1) absent from support of size 492
missing: floor coloring (2, 3, 2, 3, 2, 3) absent from support of size 720
```
(`n = 3` is trivial — only one support type. `n = 5` happens to
satisfy containment in the searched window but only against a single
other support, so the data is too thin to be evidence either way.)
The missing colorings cluster on **bipartite alternations**
(`(1,2,1,2)`, `(2,3,2,3,2,3)`) and **3-periodic patterns**
(`(1,3,2,1,3,2)`). These are the most "structured" colorings of `C_n`
— colorings the thin `m = 3` annulus is free to produce, but other
tires (with larger annulus / heavier chord patterns) actively forbid
because their interior forces additional colour variety.
**Consequence.** The simple structural shortcut — "all supports
contain a common floor, hence pairwise intersections are trivially
non-empty" — does not hold. Same-`n` compatibility (which by `4CT` is
still forced to hold) cannot be reduced to a single containment fact;
it requires a finer structural analysis of *which* colorings sit in
*which* supports, or a different shortcut entirely.
+43 -26
View File
@@ -1,72 +1,89 @@
\relax
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[]\OT1/cmr/m/n/10 Length lower bound (Birkhoff). \OT1/cmr/m/it/10 Ev-ery non-tr
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@@ -82,6 +82,40 @@ companion paper \cite{bauerfeld-nested-tire-duals} uses these
definitions to develop nested-cycle structure theorems and
chain-pigeonhole conjectures for tire annular subgraphs of $G'$.
\paragraph{Related work.}
The structural object underlying this programme --- the set of
proper $4$-colourings of a boundary cycle that extend to a colouring
of a bounded planar region --- is classical. Birkhoff's reducibility
analysis of the diamond configuration~\cite{birkhoff-reducibility} is
the earliest instance of computing such extension sets to attack the
Four Colour Theorem; the chromatic polynomial framework of Birkhoff
and Lewis~\cite{birkhoff-lewis-chromatic} systematised the counting.
Tutte studied how the chromatic polynomial of a rooted planar
triangulation decomposes along its outer
boundary~\cite{tutte-chromatic-sums-1973} and developed an algebraic
theory of graph colourings organised around separating
subgraphs~\cite{tutte-algebraic-colorings, tutte-four-colour-conjecture}.
The most recent and structurally closest parallel is Dvo\v{r}\'ak
and Lidick\'y's analysis of \emph{coloring count
cones}~\cite{dvorak-lidicky-cones}, which characterises the possible
boundary-extension functions on a fixed outer cycle of a
near-triangulation. The Heesch--Appel--Haken
approach~\cite{heesch-untersuchungen, robertson-sanders-seymour-thomas}
also uses boundary-extension reasoning, but case-by-case on a finite
unavoidable set of local configurations rather than as part of a
global structural induction.
The tire-tree decomposition introduced here differs from each of
these in shape rather than ingredients. Birkhoff, Tutte, and
Dvo\v{r}\'ak--Lidick\'y all study \emph{one} boundary; Heesch and
the cleaned-up Appel--Haken proof~\cite{robertson-sanders-seymour-thomas}
study a finite collection of local boundaries. The present framework
organises the entire triangulation into a hierarchy of annular
regions glued along level cycles, and asks whether boundary-extension
constraints compose compatibly up the hierarchy. To the authors'
knowledge, no prior work on the Four Colour Theorem has been
organised around a global nested-cycle decomposition of this kind.
Throughout, $G = (V, E)$ is a plane maximal planar graph (a triangulation)
with a fixed planar embedding $\Pi_G$. We write $|V| = n$, so $|E| = 3n - 6$
and $G$ has $2n - 4$ triangular faces.
@@ -1373,35 +1407,6 @@ inner-boundary three-colour restriction with respect to
$\mathcal{T}(G, \{v_0\})$.
\end{conjecture}
\begin{remark}[Relation to the level-cycle conjecture]
\label{rem:inner-boundary-vs-level-cycle}
For a depth-$d$ tire $T$, the inner outerplanar graph satisfies
$O^{(T)} \subseteq G[L_{d+1}]$: a depth-$d$ face has its three vertex
levels in $\{d, d+1\}$ (adjacent vertices differ by at most one level),
so the level-$(d+1)$ vertices of the tire's dual component are exactly
$V(O^{(T)})$. Since $O^{(T)}$ is outerplanar, every one of its vertices
lies on the inner-boundary walk, whence $V(B_{\mathrm{in}}^{(T)}) =
V(O^{(T)}) \subseteq L_{d+1}$ is supported on a single level, and is a
simple level cycle when $O^{(T)}$ is $2$-connected.
Consequently the vertex-source form of
Conjecture~\ref{conj:level-cycle-three-colour} implies
Conjecture~\ref{conj:tire-inner-boundary-three-colour} on every
$2$-connected inner boundary: the witnessing colouring already makes
each such cycle omit a colour. The present conjecture is thus a
\emph{weakening}, constraining only the inner-boundary cycles of one
tire-tree decomposition rather than all level cycles of some level
source. It is no harder than the vertex-source form of
Conjecture~\ref{conj:level-cycle-three-colour}, while targeting exactly
the interface the chromatic-transfer machinery of
Theorem~\ref{thm:tire-chromatic-polynomial-transfer} runs across.
(The non-$2$-connected case --- an
inner boundary whose walk traverses a bridge or cut-vertex of $O^{(T)}$
--- is not covered by the simple-cycle statement of
Conjecture~\ref{conj:level-cycle-three-colour} and must be argued
separately.)
\end{remark}
\subsection*{A counterexample at $n=14$}
Conjecture~\ref{conj:tire-inner-boundary-three-colour} is in fact
@@ -1452,38 +1457,18 @@ $17,28,69$ together with $12$.}
The failure was verified by enumerating, for each of the $14$ vertex
sources, all $96$ proper $4$-colourings of $G^\star$ and computing the
inner boundary $V(B_{\mathrm{in}}^{(T)})$ of every tire $T$ as the
level-$(d+1)$ vertices of the corresponding depth-$d$ dual component
(Remark~\ref{rem:inner-boundary-vs-level-cycle}). Each source has
exactly two non-degenerate inner boundaries (size $\geq 4$), and every
proper $4$-colouring assigns all four colours to at least one of them.
level-$(d+1)$ vertices of the corresponding depth-$d$ dual component.
Each source has exactly two non-degenerate inner boundaries
(size $\geq 4$), and every proper $4$-colouring assigns all four
colours to at least one of them.
Because Conjecture~\ref{conj:tire-inner-boundary-three-colour} is a
weakening of the vertex-source form of
Conjecture~\ref{conj:level-cycle-three-colour} only \emph{on
$2$-connected inner boundaries}
(Remark~\ref{rem:inner-boundary-vs-level-cycle}), $G^\star$ need not
refute Conjecture~\ref{conj:level-cycle-three-colour}, and in fact does
not: the vertex source $v_0 = 10$ admits a proper $4$-colouring under
which every simple level cycle uses at most three colours. Combining
this with Remark~\ref{rem:inner-boundary-vs-level-cycle}, at least one
tire $T$ under $v_0 = 10$ must have an inner outerplanar graph
$O^{(T)}$ that fails to be $2$-connected --- under the witnessing
colouring, some inner boundary uses all four colours, and if its
$O^{(T)}$ were $2$-connected then by
Remark~\ref{rem:inner-boundary-vs-level-cycle} that inner boundary
would be a simple level cycle, contradicting the level-cycle witness.
The failure of
Conjecture~\ref{conj:tire-inner-boundary-three-colour} is therefore
attributable to the non-$2$-connected case left open by
Remark~\ref{rem:inner-boundary-vs-level-cycle}, not to a deeper failure
of the level-cycle statement on $G^\star$.
The graph $G^\star$ does not refute
Conjecture~\ref{conj:level-cycle-three-colour}: the vertex source
$v_0 = 10$ admits a proper $4$-colouring under which every simple level
cycle uses at most three colours.
\subsection*{The surviving level-cycle conjecture}
The verification on $G^\star$ above is consistent with the broader
empirical picture for the level-cycle restriction, which we record as
the conjecture this section ultimately stands on.
\begin{conjecture}[Level-cycle three-colour conjecture]
\label{conj:level-cycle-three-colour}
Let $G$ be a maximal planar graph. Then there exists a level source
@@ -1703,6 +1688,46 @@ E.~Bauerfeld,
\emph{Coloring Nested Tire Dual Graphs},
manuscript (math-research repository), 2026.
\bibitem{birkhoff-reducibility}
G.~D.~Birkhoff,
\emph{The reducibility of maps},
Amer.\ J.\ Math.\ \textbf{35} (1913), 115--128.
\bibitem{birkhoff-lewis-chromatic}
G.~D.~Birkhoff and D.~C.~Lewis,
\emph{Chromatic polynomials},
Trans.\ Amer.\ Math.\ Soc.\ \textbf{60} (1946), 355--451.
\bibitem{tutte-four-colour-conjecture}
W.~T.~Tutte,
\emph{On the four-colour conjecture},
Proc.\ London Math.\ Soc.\ (2) \textbf{50} (1948), 137--149.
\bibitem{tutte-algebraic-colorings}
W.~T.~Tutte,
\emph{On the algebraic theory of graph colorings},
J.\ Combin.\ Theory \textbf{1} (1966), 15--50.
\bibitem{tutte-chromatic-sums-1973}
W.~T.~Tutte,
\emph{Chromatic sums for rooted planar triangulations: the cases $\lambda = 1$ and $\lambda = 2$},
Canad.\ J.\ Math.\ \textbf{25} (1973), 426--447.
\bibitem{heesch-untersuchungen}
H.~Heesch,
\emph{Untersuchungen zum Vierfarbenproblem},
Hochschulskriptum 810/a/b, Bibliographisches Institut, Mannheim, 1969.
\bibitem{robertson-sanders-seymour-thomas}
N.~Robertson, D.~P.~Sanders, P.~D.~Seymour, and R.~Thomas,
\emph{The four-colour theorem},
J.\ Combin.\ Theory Ser.\ B \textbf{70} (1997), 2--44.
\bibitem{dvorak-lidicky-cones}
Z.~Dvo\v{r}\'ak and B.~Lidick\'y,
\emph{Coloring count cones of planar graphs},
J.\ Graph Theory \textbf{100} (2022), 84--100.
\end{thebibliography}
\end{document}