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Add the freedom-positive counting balance to the constraint floor

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Remark: a disk with k interior vertices has 2k+n-2 faces (Euler) but only
k interior constraints, so each interior vertex adds two degrees of
freedom against one constraint -- depth is freedom-positive and Phi can
only retain or enlarge below the interior-free floor 2^(n-2). Motivates
the lower bound and replaces the prior TODO sketch.

Co-Authored-By: Claude Opus 4.8 <noreply@anthropic.com>
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2026-06-17 02:24:04 -04:00
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papers/heawood_restrictions_on_nested_tire_graph_duals/paper.aux
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\bibcite{bauerfeld-depth}{2} \bibcite{bauerfeld-depth}{2}
\bibcite{bauerfeld-nested-tires}{3} \bibcite{bauerfeld-nested-tires}{3}
\bibcite{bauerfeld-medial-tires}{4} \bibcite{bauerfeld-medial-tires}{4}
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\@writefile{toc}{\contentsline {section}{\tocsection {}{}{References}}{6}{}\protected@file@percent }
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papers/heawood_restrictions_on_nested_tire_graph_duals/paper.log
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papers/heawood_restrictions_on_nested_tire_graph_duals/paper.pdf
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papers/heawood_restrictions_on_nested_tire_graph_duals/paper.tex
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@@ -499,12 +499,23 @@ the boundary sequence, so the map $\lambda \mapsto \lambda^{*}|_C$ is
injective and $|\Phi(D)| = 2^{\,n-2}$. injective and $|\Phi(D)| = 2^{\,n-2}$.
\end{proof} \end{proof}
%% TODO (lower bound): show |Phi(D)| >= 2^{n-2} for EVERY triangulated \begin{remark}[Depth is freedom-positive]
%% disk D. Strategy: the n boundary-incident faces (one per boundary edge) \label{rem:freedom-positive}
%% carry n-2 independent binary degrees of freedom after the interior The lower bound is plausible from a counting balance. A triangulated
%% Heawood constraints are imposed; those constraints relate only disk with $k$ interior vertices has $2k + n - 2$ faces (Euler) and
%% interior-incident faces and cannot collapse the boundary freedom below imposes exactly $k$ interior Heawood constraints, one per interior
%% 2^{n-2}. (See notes/boundary_restriction_structure.tex.) vertex. So each interior vertex contributes \emph{two} faces --- two new
$\{+1,-1\}$ degrees of freedom --- against only \emph{one} constraint,
and the free dimension $(2k + n - 2) - k = k + n - 2$ \emph{grows} with
depth. Going deeper is freedom-positive on balance: the boundary
projection $\Phi(D)$ can only retain or enlarge its options, never drop
below the interior-free value $2^{\,n-2}$. (Empirically $|\Phi(D)|$ does
grow with $k$; e.g.\ on the $4$-cycle the central-apex wheel realises $5$
sequences against the fan's $4$.) The constraints relate only
interior-incident faces and cannot collapse the $n-2$ degrees of freedom
carried by the boundary-incident faces --- which is the content the lower
bound must make precise.
\end{remark}
\begin{remark} \begin{remark}
\label{rem:floor-consequences} \label{rem:floor-consequences}