Reframe the constraint floor honestly as a conjecture

Section 4 no longer states the floor as a proven Proposition. Now: prove
interior-free disks attain 2^(n-2) (ear-peeling) and the un-stacking
lemma, state |Phi(D)| >= 2^(n-2) as a Conjecture, and give an honest
status remark -- holds for the Apollonian class, reduces to the
irreducible case, empirically strict (5/4), but |Phi| is NOT monotone
(the earlier freedom-positive monotonicity claim was wrong) and both
natural elementary proofs provably fail. Soften the note's observation to
match.

Co-Authored-By: Claude Opus 4.8 <noreply@anthropic.com>
This commit is contained in:
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@@ -102,10 +102,11 @@ realises $5$ sequences against the fan's $4$, since each interior vertex
contributes two faces but only one constraint. Thus:
\begin{obs}
The outer $n$-cycle cannot be constrained below $2^{n-2}$ achievable
sequences, and no nested structure is needed to reach the floor: a single
trivial tire is already maximal. Deep nesting only approaches the floor
from above.
The interior-free triangulation already attains $2^{n-2}$, no search disk
beats it, and deep nesting only approaches this value from above ---
suggesting it is a floor, with a single trivial tire already maximally
constraining. Whether $2^{n-2}$ is a genuine lower bound for \emph{all}
disks is the Conjecture below; it is \emph{not} a proven theorem.
\end{obs}
The achievability is transparent: in a fan from $v_0$,