Reframe the constraint floor honestly as a conjecture
Section 4 no longer states the floor as a proven Proposition. Now: prove interior-free disks attain 2^(n-2) (ear-peeling) and the un-stacking lemma, state |Phi(D)| >= 2^(n-2) as a Conjecture, and give an honest status remark -- holds for the Apollonian class, reduces to the irreducible case, empirically strict (5/4), but |Phi| is NOT monotone (the earlier freedom-positive monotonicity claim was wrong) and both natural elementary proofs provably fail. Soften the note's observation to match. Co-Authored-By: Claude Opus 4.8 <noreply@anthropic.com>
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contributes two faces but only one constraint. Thus:
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\begin{obs}
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The outer $n$-cycle cannot be constrained below $2^{n-2}$ achievable
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sequences, and no nested structure is needed to reach the floor: a single
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trivial tire is already maximal. Deep nesting only approaches the floor
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from above.
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The interior-free triangulation already attains $2^{n-2}$, no search disk
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beats it, and deep nesting only approaches this value from above ---
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suggesting it is a floor, with a single trivial tire already maximally
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constraining. Whether $2^{n-2}$ is a genuine lower bound for \emph{all}
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disks is the Conjecture below; it is \emph{not} a proven theorem.
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\end{obs}
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The achievability is transparent: in a fan from $v_0$,
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