coloring_nested_tire_graphs: partial proof of closed-chain non-emptiness identifies the 4CT-equivalent gap
Attempts to prove item 1 (non-emptiness of state at L_n in closed
SR+PDS chains ending at outer triangle). Results:
PROVEN:
- S_3-closure preserved by chain propagation.
- State at L_n is either empty OR equals all 6 permutations of {1,2,3}
(the only non-empty S_3-closed subset of permutations).
- Non-emptiness propagates through intermediate tires under outward
PDS via step-1 saturation.
REMAINING GAP (conjecture, empirically true): state at L_{n-1}
intersects the "perm-paired" subset of T_n's σ_D-projection (the
σ_D values that pair with permutation σ_U). At the final step T_n
has m_n=3 < k_n, so saturation fails — chain state at L_{n-1} could
in principle lie entirely in the (non-perm-paired) parity-matching
σ_D's, but empirically doesn't.
KEY STRUCTURAL FINDING: for T=(3, k), the σ_D's paired with a
permutation σ_U equal exactly the (parity-matching σ_D's) ∩ (T's
σ_D-projection). Verified for k=3..10.
HONEST OBSERVATION: a structural proof of the remaining conjecture
(without invoking 4CT) would constitute a new proof of 4CT under
the SR+PDS modelling assumption. The chain-pigeonhole framework
reduces to this single reachability question.
Co-Authored-By: Claude Opus 4.7 <noreply@anthropic.com>
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\documentclass[11pt]{article}
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\usepackage{amsmath,amssymb,amsthm}
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\usepackage{graphicx}
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\usepackage{geometry}
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\geometry{margin=1in}
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\title{Closed-chain non-emptiness: a partial proof and the remaining gap}
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\author{}
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\date{}
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\newtheorem{lemma}{Lemma}
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\newtheorem{theorem}{Theorem}
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\newtheorem{corollary}[lemma]{Corollary}
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\newtheorem*{conj}{Conjecture}
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\begin{document}
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\maketitle
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\section*{What this note records}
|
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In \texttt{absorption\_proof.tex} we proved (via the $K_3$-walk parity
|
||||
invariant) that the forward-propagated state at $L_n$ of a closed
|
||||
SR + PDS chain ending at the outer triangle is contained in the $6$
|
||||
permutations of $\{1, 2, 3\}$. This note attempts to prove the
|
||||
remaining ``non-emptiness'' half: that the state is non-empty (and
|
||||
hence, by $S_3$ invariance, equals all $6$).
|
||||
|
||||
\textbf{Result so far:} the proof closes \emph{conditionally} on a
|
||||
specific structural property of $T_n$ that holds empirically but I
|
||||
have not proven in general.
|
||||
|
||||
\section*{What's easy}
|
||||
|
||||
\begin{lemma}[$S_3$-closure preserved by chain propagation]
|
||||
\label{lem:s3-closure}
|
||||
For any SR chain $T_1 | \dots | T_n$ starting from a degenerate-inner
|
||||
$T_1$, the forward-propagated state at every $L_i$ is closed under
|
||||
the $S_3$ action on colours.
|
||||
\end{lemma}
|
||||
|
||||
\begin{proof}
|
||||
Each tire's joint support $\Pi_{T_i}$ is determined by the proper
|
||||
edge $3$-colourings of $T_i$'s annular dual cycle. The $S_3$ action
|
||||
on the three colour labels acts uniformly on $C_{n_i}$-colourings,
|
||||
so $\Pi_{T_i}$ is closed under the diagonal $S_3$ action. Forward
|
||||
propagation $\text{state}_{i+1} = \{ \sigma_U : \exists \sigma_D \in
|
||||
\text{state}_i, (\sigma_U, \sigma_D) \in \Pi_{T_{i+1}}\}$ commutes
|
||||
with $S_3$: if $\sigma$ is in $\text{state}_{i+1}$ via some
|
||||
$\sigma_D \in \text{state}_i$, then $g \cdot \sigma$ is in
|
||||
$\text{state}_{i+1}$ via $g \cdot \sigma_D \in \text{state}_i$
|
||||
(using $S_3$-closure of $\text{state}_i$ inductively).
|
||||
\end{proof}
|
||||
|
||||
\begin{theorem}[Conditional non-emptiness $\Rightarrow$ exactly 6]
|
||||
\label{thm:six-or-zero}
|
||||
The forward-propagated state at $L_n$ is either empty, or equals all
|
||||
$6$ permutations of $\{1, 2, 3\}$.
|
||||
\end{theorem}
|
||||
|
||||
\begin{proof}
|
||||
By the parity invariant (proved in
|
||||
\texttt{absorption\_proof.tex}), $\text{state}(L_n) \subseteq$
|
||||
permutations of $\{1,2,3\}$. The $6$ permutations form a single
|
||||
$S_3$-orbit (the $S_3$ action on length-$3$ tuples with $3$ distinct
|
||||
colours is transitive). By Lem.~\ref{lem:s3-closure},
|
||||
$\text{state}(L_n)$ is $S_3$-closed. An $S_3$-closed subset of a
|
||||
single $S_3$-orbit is either empty or the whole orbit.
|
||||
\end{proof}
|
||||
|
||||
So non-emptiness $\Leftrightarrow$ state $= 6$ permutations.
|
||||
|
||||
\section*{Non-emptiness for intermediate steps}
|
||||
|
||||
\begin{lemma}[Saturation preserves non-emptiness in the outward
|
||||
direction]
|
||||
\label{lem:saturation-nonempty}
|
||||
If $T_{i+1}$ has $m_{i+1} \geq k_{i+1}$ (the outward-PDS condition),
|
||||
then $\text{state}(L_{i+1})$ is non-empty whenever $\text{state}(L_i)$
|
||||
is non-empty.
|
||||
\end{lemma}
|
||||
|
||||
\begin{proof}
|
||||
By the spread-projection saturation theorem from step 1, when $m_{i+1}
|
||||
\geq k_{i+1}$ the $\sigma_D$-projection of $\Pi_{T_{i+1}}$ equals all of
|
||||
$\{1, 2, 3\}^{k_{i+1}}$. Hence
|
||||
$\text{state}(L_i) \subseteq \{1,2,3\}^{k_{i+1}} = \sigma_D
|
||||
\text{-projection of } T_{i+1}$, so every $\sigma_D \in
|
||||
\text{state}(L_i)$ is in some pair of $\Pi_{T_{i+1}}$. Thus
|
||||
$\text{state}(L_{i+1}) \ni \sigma_U$ for at least one $\sigma_U$
|
||||
paired with some $\sigma_D$ in the state. Since
|
||||
$\text{state}(L_i) \neq \emptyset$, $\text{state}(L_{i+1}) \neq
|
||||
\emptyset$.
|
||||
\end{proof}
|
||||
|
||||
\begin{corollary}[Open-chain non-emptiness]
|
||||
\label{cor:open-nonempty}
|
||||
For any prefix $T_1 | T_2 | \dots | T_j$ of an outward-PDS chain with
|
||||
$T_1$ degenerate-inner and each subsequent $T_{i+1}$ satisfying
|
||||
$m_{i+1} \geq k_{i+1}$, the state at $L_j$ is non-empty.
|
||||
\end{corollary}
|
||||
|
||||
\begin{proof}
|
||||
$\text{state}(L_1)$ equals the σ-set from proper edge $3$-colourings
|
||||
of $C_{m_1}$, which has $2^{m_1} + 2(-1)^{m_1} > 0$ elements for
|
||||
$m_1 \geq 3$. Iterate Lem.~\ref{lem:saturation-nonempty}.
|
||||
\end{proof}
|
||||
|
||||
\section*{The remaining piece: the final step at $T_n$}
|
||||
|
||||
The final step $T_n$ has $m_n = 3$ (outer triangle). Since $|L_{n-1}|
|
||||
= k_n \geq 3$ in any non-trivial PDS, typically $k_n \geq 3 = m_n$
|
||||
and the inequality is reversed.
|
||||
|
||||
When $m_n < k_n$ the saturation theorem fails: $T_n$'s
|
||||
σ$_D$-projection is a proper subset of $\{1,2,3\}^{k_n}$. Concretely:
|
||||
|
||||
\begin{center}
|
||||
\small
|
||||
\begin{tabular}{c r r r r}
|
||||
\toprule
|
||||
$k$ & $|\Pi_{T_n}|$ & $|\sigma_D\text{-proj}|$ & $|\text{parity set}|$ & $|\sigma_D \cap \text{parity}|$ \\
|
||||
\midrule
|
||||
3 & 63 & 27 & 6 & 6 \\
|
||||
5 & 255 & 171 & 60 & 42 \\
|
||||
6 & 510 & 384 & 183 & 90 \\
|
||||
9 & 4095 & 3681 & 4920 & 840 \\
|
||||
\bottomrule
|
||||
\end{tabular}
|
||||
\end{center}
|
||||
|
||||
\paragraph{Key observation.}
|
||||
Computationally, the set of $\sigma_D$'s in $T_n$'s
|
||||
$\sigma_D$-projection that are \emph{also} parity-matching equals
|
||||
exactly the set of $\sigma_D$'s that pair with a permutation $\sigma_U$
|
||||
under $\Pi_{T_n}$. Call this set the ``perm-paired'' subset.
|
||||
|
||||
For non-emptiness at $L_n$ we need: \textbf{$\text{state}(L_{n-1})$
|
||||
intersects the perm-paired subset of $T_n$}.
|
||||
|
||||
\section*{Restatement of the remaining gap}
|
||||
|
||||
\begin{conj}[Perm-paired reachability]
|
||||
\label{conj:perm-reach}
|
||||
For any SR + outward-PDS chain $T_1 | \dots | T_{n-1}$ with $T_1$
|
||||
degenerate-inner, the forward-propagated state at $L_{n-1}$ contains
|
||||
at least one $\sigma_D$ that is in the perm-paired subset of $T_n =
|
||||
(3, k_n)$ (i.e., a $\sigma_D$ such that $(\sigma_U, \sigma_D) \in
|
||||
\Pi_{T_n}$ for some permutation $\sigma_U$).
|
||||
\end{conj}
|
||||
|
||||
This is the only remaining gap. Empirically Conj.~\ref{conj:perm-reach}
|
||||
holds in every tested chain; theoretically I do not yet have a proof.
|
||||
|
||||
\subsection*{What I know about Conj.~\ref{conj:perm-reach}}
|
||||
|
||||
\begin{enumerate}
|
||||
\item By the parity invariant, $\text{state}(L_{n-1}) \subseteq$
|
||||
parity-matching set on $L_{n-1}$ (size 60 at $k = 5$).
|
||||
\item The perm-paired subset has size $\leq |\text{parity-matching}|$
|
||||
and is generally strictly smaller (at $k = 5$, $42 < 60$).
|
||||
\item Both are $S_3$-closed; both are unions of $S_3$-orbits of size $6$
|
||||
(no constant orbits, since constants violate parity).
|
||||
\item Empirically, at sufficiently late stages, $\text{state}(L_{n-1})
|
||||
= $ full parity-matching set. Since the perm-paired subset is
|
||||
strictly contained in the parity-matching set, the intersection
|
||||
is the perm-paired subset itself (non-empty).
|
||||
\item A clean proof of Conj.~\ref{conj:perm-reach} would seem to
|
||||
require either (a) showing chain state always equals the full
|
||||
parity-matching set at $L_{n-1}$, or (b) an explicit
|
||||
construction of a perm-paired $\sigma_D$ reachable through any
|
||||
outward-PDS chain.
|
||||
\end{enumerate}
|
||||
|
||||
\subsection*{Why it's not immediate from saturation}
|
||||
|
||||
Lem.~\ref{lem:saturation-nonempty} preserves \emph{some} non-empty
|
||||
state, but doesn't characterise \emph{which} σ values are in the state.
|
||||
A more refined statement is needed: state at each $L_i$ equals the
|
||||
full parity-matching set (or at least a strictly-larger-than-empty
|
||||
subset of perm-paired$_{T_n}$).
|
||||
|
||||
\subsection*{Why a Tait+4CT reduction is circular}
|
||||
|
||||
In general, ``state at $L_n$ non-empty'' is equivalent to the chain's
|
||||
underlying cubic planar graph $G'$ admitting a proper edge
|
||||
$3$-colouring, which by Tait's theorem is equivalent to $G$ being
|
||||
$4$-colourable. So Conj.~\ref{conj:perm-reach} for arbitrary
|
||||
outward-PDS chains under SR is essentially the 4CT itself (or rather,
|
||||
4CT restricted to graphs admitting SR + outward-PDS decompositions).
|
||||
|
||||
This means Conj.~\ref{conj:perm-reach} cannot be proven by invoking
|
||||
4CT --- but a \emph{structural} proof of it, independent of 4CT,
|
||||
\emph{would constitute} a new proof of 4CT (under the SR + PDS
|
||||
modelling assumption).
|
||||
|
||||
\section*{Summary}
|
||||
|
||||
\begin{itemize}
|
||||
\item \textbf{Proven:} state at $L_n$ is either empty or equals
|
||||
all 6 permutations of $\{1,2,3\}$ (Thm.~\ref{thm:six-or-zero}).
|
||||
\item \textbf{Proven:} non-emptiness propagates through all
|
||||
intermediate tires under outward PDS
|
||||
(Cor.~\ref{cor:open-nonempty}).
|
||||
\item \textbf{Conjectured (Conj.~\ref{conj:perm-reach}):}
|
||||
non-emptiness propagates through the final tire $T_n$.
|
||||
Empirically true; structural proof would imply 4CT.
|
||||
\end{itemize}
|
||||
|
||||
The clean conclusion: \textbf{the chain-pigeonhole story under SR + PDS
|
||||
reduces to one specific reachability conjecture about chain states
|
||||
hitting the perm-paired subset of the final tire}. This is the
|
||||
sharpest version of the 4CT obstruction in our framework.
|
||||
|
||||
\end{document}
|
||||
Reference in New Issue
Block a user